In the waves lab you change blank to see how it would affect wave speed

A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material

Llana [10]

Answer:

a) $C = 40.138\,pF$ , b) $q = 16.056\,nC$ , c) $U = 3.212\,\mu J$

Explanation:

a) The capacitance of two parallel plates capacitor with dielectric is given by the following expression:

$C = K\cdot \epsilon_{o}\cdot \frac{A}{d}$

Where:

$K$ - Dielectric constant.

$\epsilon_{o}$ - Vaccum permitivity.

$A$ - Plate area.

$d$ - Distance between plates.

Hence, the capacitance of the system is:

$C = (4.00)\cdot (8.854\times 10^{-12}\,\frac{F}{m} )\cdot \left(\frac{17\times 10^{-4}\,m^{2}}{0.150\times 10^{-2}\,m}\right)$

$C = 4.014\cdot 10^{-11}\,F$

$C = 40.138\,pF$

b) The charge can be found by using the definition of capacitance:

$q = C\cdot V_{batt}$

$q = (4.014\times 10^{-11}\,F)\cdot (400\,V)$

$q = 1.606\times 10^{-8}\,C$

$q = 16.056\,nC$

c) The energy stored in the charged capacitor is:

$U=\frac{1}{2}\cdot Q\cdot V_{batt}$

$U=\frac{1}{2}\cdot (1.606\times 10^{-8}\,C)\cdot (400\,V)$

$U = 3.212\times 10^{-6}\,J$

$U = 3.212\,\mu J$

3 0

3 years ago

Read 2 more answers

What do you mean by 100W is written on an electric bulb?

Goryan [66]

Answer:

100 watt

Watt is a unit of power, for the light bulb its produces or consumes 100 watts of power

7 0

3 years ago

Read 2 more answers

What is the mass of 3.70 L of water? Remember 1000 L = 1 m^3 (Unit=Kg)

xxMikexx [17]

Answer:

3.7kg

Explanation:

The following data were obtained from the question:

Volume = 3.7L

Mass =?

Next, we shall convert 3.7L to m³.

This is illustrated below:

1000L = 1m³

Therefore, 3.7L = 3.7/1000 = 0.0037m³

Now, we can obtain the mass of the water as shown below:

Density of water = 1000kg/m³

Volume of water = 0.0037m³

Mass of water =..?

Density = Mass /volume

1000kg/m³ = Mass /0.0037m³

Cross multiply

Mass = 1000Kg/m³ × 0.0037m³

Mass = 3.7Kg

Therefore, the mass of the water is 3.7Kg.

8 0

3 years ago

If a 0.50-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 3.7 N for a distance of 6

mel-nik [20]

The block's velocity is determined as 10.03 m/s.

<u>Explanation:</u>

According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.

So, work done = Kinetic energy

$\text {Force } \times \text { displacement }=\frac{1}{2} \times m \times v^{2}$

Thus, the velocity can be determined as

$\text {velocity}=\sqrt{\frac{2 \times \text {Force} \times \text {displacement}}{m}}$

$\text {velocity}=\sqrt{\frac{2 \times 3.7 \times 6.8}{0.50}}=\sqrt{\frac{50.32}{0.50}}=\sqrt{100.64}$

Velocity = 10.03 m/s.

So the block's velocity is determined as 10.03 m/s.

5 0

4 years ago

The Sun is to a planet as -

serg [7]

Answer:a

Explanation:

5 0

3 years ago

In the waves lab you change blank to see how it would affect wave speed​

In the waves lab you change blank to see how it would affect wave speed