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Setler79 [48]
2 years ago
7

What type of reaction is: br2 + nal2 ---> nabr + l2

Chemistry
1 answer:
Furkat [3]2 years ago
6 0

Answer: its a single replacement reaction

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List of 10 strong bases and acids?
tatyana61 [14]
<span><span>KaAcid</span><span><span>1.0 * 109</span>Hydrobromic acidHBr</span><span><span>1.3 * 106</span>Hydrochloric acidHCl</span><span><span>1.0 * 103</span>Sulfuric acid<span>H2SO4</span></span><span><span>2.4 * 101</span>Nitric acid<span>HNO<span>3</span></span></span></span>
4 0
3 years ago
Consider the following reaction: 3Fe(s) + 4H₂O(g) ➞ Fe₃O₄(s) + 4H₂(g). To answer the following question: "How many moles of hot
Elodia [21]

Answer: 2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} Fe_3O_4=\frac{275g}{233.5g/mol}=1.18moles

3Fe(s)+4H_2O(g)\rightarrow Fe_3O_4(s)+4H_2(g)  

According to stoichiometry :

1 mole of Fe_3O_4 are produced by = 4 moles of H_2O

Thus 1.18 moles of Fe_3O_4 will be produced by=\frac{4}{1}\times 1.18=4.72moles  of H_2O

Mass of H_2O=moles\times {\text {Molar mass}}=4.72moles\times 18g/mol=85.0g

Thus 85.0  g of H_2O will be required and 2 steps are required to get the answer.

6 0
3 years ago
The ____ is the time required for one half of the atoms of a radio scope to ____.
mash [69]
First blank is: Half-Life
Second Blank is: decay into its products
7 0
3 years ago
3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,
VARVARA [1.3K]

Answer:

Cp_{liquid}=2.54\frac{J}{g\°C}

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

Q_{Ag}=-Q_{liquid}

That in terms of the heat capacities, masses and temperature changes turns out:

m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}

Best regards.

6 0
3 years ago
What is the formula for the ionic compound formed between sodium and oxygen?
CaHeK987 [17]

Answer:The formula for the compound formed between sodium and oxygen will be Na2O; a ratio of 2 Na atoms for each O atom.

Explanation:

8 0
2 years ago
Read 2 more answers
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