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kifflom [539]
3 years ago
13

A ball is tossed in the air and released. It moves up, reverses direction, falls back down again, and is caught at the same heig

ht it was released. Considering the time interval after the ball is released and before it is caught, when does the gravitational potential energy of the ball have its maximum value?
Physics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

The potential energy has a  maximum when the ball is a time that is half of the time for total travel

Explanation:

Generally potential energy is a the varies directly with the height according to this formula

            PE =mgh

and the ball attains a maximum height when the time is equal to half of the total time taken to travel  

Anni [7]3 years ago
3 0

Answer:

The potential energy is highest at it point of Max height...

Explanation:

From the formula potential energy = mgh...

The greater the height, the greater the potential energy.

So considering the time interval it's at the time it takes the ball to reach the reversal point ( its Max height)

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A technique in which people use machines to learn how to control their bodies is known as __________.
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A cyclist travels at a speed of 21.6km/h.
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Answer:

D.6.0m/s

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3 0
2 years ago
You lay a mirror flat on the floor with one edge against a wall and aim a laser at the mirror. The ray reflects from the mirror
joja [24]

Answer:

the angle of incidence θ is 45.56 º

Explanation:

Given data

strikes the mirror before wall x = 30.7 cm

reflected ray strikes the wall y =  30.1 cm

to find out

the angle of incidence θ

solution

let us consider ray is strike at angle  θ so after strike on surface ray strike to wall at angle 90 - θ

we will apply here right angle triangle rule that is

tan( 90 - θ) = y /x

tan( 90 - θ)  = 30.1 / 30.7

90 - θ = tan^-1 (30.1/30.7)

90 - θ = 44.4345

θ = 45.56 º

the angle of incidence θ is 45.56 º

4 0
3 years ago
The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material
aleksklad [387]

Answer:

Capacitance is 0.572×10⁻¹⁰ Farad

Explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

Capacitance\ (C)=\frac{4\pi k\epsilon_0 R_1\times R_2}{R_2-R_1}\\\Rightarrow C=\frac{4\pi 4.8\times 8.854\times 10^{-12}\times 15\times 10^{-2}\times 6.25\times 10^{-2}}{15\times 10^{-2}-6.25\times 10^{-2}}\\\Rightarrow C=0.572\times 10^{-10}\ Farad

∴ Capacitance is 0.572×10⁻¹⁰ Farad

3 0
3 years ago
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