<img src="https://tex.z-dn.net/?f=6%20%2B%20%20%5Cfrac%7Bv%7D%7B%20-%208%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B7%7D%20" id="TexFormu

All categories

3 years ago

la1" title="6 + \frac{v}{ - 8} = \frac{4}{7} " alt="6 + \frac{v}{ - 8} = \frac{4}{7} " align="absmiddle" class="latex-formula">
I don't understand how to solve for V.

Mathematics

1 answer:

Kay [80]3 years ago

8 0

-304/7 is your answer

You might be interested in

Solve the equation using the quadratic formula

amm1812

Answer:

Step-by-step explanation:

Rewrite this quadratic equation in standard form: 2n^2 + 3n + 54 = 0. Identify the coefficients of the n terms: they are 2, 3, 54.

Find the discriminant b^2 - 4ac: It is 3^2 - 4(2)(54), or -423. The negative sign tells us that this quadratic has two unequal, complex roots, which are:

-(3) ± i√423 -3 ± i√423

n = ------------------- = ------------------

2(2) 4

3 0

2 years ago

Round 7.2242 to the nearest hundredth

alukav5142 [94]

7.22 is 7.2242 rounded to the neartest hundreth

8 0

3 years ago

Help Friends, Ayuda Amigos :(.

mojhsa [17]

Answer:

i dont speak spanish

Step-by-step explanation:

sorry i dont understand you...

4 0

2 years ago

The graph of which function passes through (0,4) and has a minimum value at (StartFraction 3 pi Over 2 EndFraction, 3)? f (x) =

solniwko [45]

Answer:

f(x) = sin(x) + 4 Let me know if you don't see why.

Step-by-step explanation:

As much as I hate it I think it might be best to check each one.

sin(x) has a point at (0,0) so that's not right.

sin(x)+4 has (0,4) as a point and a minimum at (3*pi/2+2*pi*n,3) where n is some integer. if we have n = 0 then it becomes (3*pi/2, 3) So that looks like our answer.

cos(x) + 3 has a point at (0,4) then minimums at (pi+2*pi*n, 2) the y coordinate is wrong so this won't work

-3sin(x) has a point at (0,0) so that's wrong

4cos(x) has a point at (0,4) then minimums at (pi+2*pi*n, -4) which again has the wrong y value so this is wrong.

Let me know if you don't understand how I got the results I did, I would be happy to explain.

7 0

2 years ago

Read 2 more answers

Will mark brainliest if fast

marshall27 [118]

Sector area can be found with the formula $A = \frac{\theta}{360} \pi r ^2$ where $\theta$ is the central angle.

r = 8m , $\theta$ = 135º

$A = \frac{135}{360} \pi (8)$ m^2

Arc length formula is $s = 2\pi r (\frac{\theta}{360} )\\$

$s = 2\pi (8)(\frac{135}{360} )\\$ m

4 0

3 years ago