I don't know if it's (1/x )+ 5 or 1/(x+5) anyways
g(x) = x-2 so in f(g(x)) you replace every x with x-2
f(g(x)) = (1/(x-2)) + 5 or 1/(x-2-5) = 1/(x-7)
if the function is like the first form so you avoid numbers which will make your denominator equals zero
x-2 = 0, x=2 or x-7 = 0, x=7
so if it's like first one answer is R - 2
if it's second answer is R - 7
3,868,000,000 is your answer. Move the decimal to the right 9 times. That gives you 6 extra 0’s.
Answer:
Please read the enswer below
Step-by-step explanation:
The quotient-remainder theorem establishes that given an integer n, there are unique integers d and r, with 0≤r<d, and such that:
q: the quotient
d: the remainder
d: divisor = 2
By the quotient-remainder theorem with divisor 2, you have:
n = 2q
n = 2q + 1
Then, for both cases you have:
(the square of an integer with divisor 2 is 4k)
with 
but 2q + 1 = n
where you have taken 
(the product 2qn is another integer)
A,B,F.....................
Answer:
cy+d to the middle of the problem
