Declining number and variety of the species in an area

Smog and other forms of pollution from urban cities can help create more carbon dioxide as well as global warming and, in turn,

bagirrra123 [75]

I believe the anawer is B, Deforestation

4 0

3 years ago

Read 2 more answers

Nitrogen fixation is A. the conversion of gaseous nitrogen into an organism friendly form (ammonia (NH3). B. preplanned setting

Stolb23 [73]

Answer:

The correct answer is option A. "the conversion of gaseous nitrogen into an organism friendly form (ammonia (NH3)".

Explanation:

Nitrogen fixation is a biological process at which gaseous nitrogen is converted into an organism friendly form (ammonia (NH3). Nitrogen fixation is performed in nature by microorganisms in the soil. Some of these microorganisms have a symbiotic relationship with plants. These microorganisms convert the gaseous nitrogen into ammonia, which is used by the plant as a source of nitrogen.

8 0

3 years ago

Ack I need help please :> its in science

mr_godi [17]

Answer:

1. Cell

2. Tissue

3. Organ

4. Organ system

5. Organism

1) Cell

2) Tissue

3) Cells

4) Organ

5) Tissues

6) Heart

7) Organs

8) Circulatory

9) Organism

10) Human

7 0

3 years ago

Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m

Vanyuwa [196]

This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
$v=\frac{2\pi{r}}{T}$
 $=\frac{2\pi{r}}{1.88*365.25*86400}$ m/s, accounting for leap years
$=3.371*10^{-8}\pi{r}$ m/s

The centripetal force, Fc, generated is
$Fc=\frac{mv^2}{r}$
where m=mass of mars = 6.39*10^(24) kg
$=\frac{mv^2}{r}$
$=\frac{6.39*10^{24}v^2}{r}$
$=7.26168*10^9\pi^2r$

The gravitation pull from the sun, Fg, is given by
$Fg=\frac{GMm}{r^2}$
where G=grav. const., =6.67408*10^(-11) m^3 kg^(-1) s^(-2)
M=mass of sun=1.989*10^(30) kg
$=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}$
$=\frac{8.4826*10^44}{r^2}$

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
$7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}$
Solving for the real root:
$r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}$
$=\frac{1.1681263*10^{35}}{\pi^2}$
=2.279*10^11 m

5 0

3 years ago

What prevents the lac genes in the DNA of E. colin from being expressed most of the time ?

Alona [7]

The lac repressor prevents the lac genes in the DNA of E. coli from being expressed most of the time. The answer to your question is A. I hope this is the answer that you are looking for and it comes to your help.

3 0

3 years ago