Answer:
A) k = 2,858 10⁴ N / m
, B) x_total = - 5,812 10⁻¹ m
C) it is very possible that the obtained value is not realistic for small vehicles
Explanation:
Part A
In this case we can use Hooke's law
F = - k x
force is the weight of the driver
F = W
mg = - k x
k = - mg / x
the springs are compressed x = - 2,4 10⁻² m
k = - 70 9.8 / (-2.4 10⁻²)
k = 2,858 10⁴ N / m
Part B
Since we have the spring constant we must find the complete weight, for this we look for the total masses
each mass is the number of element by the mass of an element
M = 23 70 + 3 15 + 5 3 + 1 25
M = 1695 kg
F = -k x
F = W = M g
Mg = - k x_total
x_total = -M g / k
x_total = -1695 9.8 / 2,858 10⁴
x_total = - 5,812 10⁻¹ m
The negative sign indicates that the springs are compressing
Part C
The truck has lowered 0.58 m = 58 cm
This drop is very large probably in a real vehicle with this drop it would be touching the ground or very close, therefore it is very possible that the obtained value is not realistic for small vehicles
