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sasho [114]
3 years ago
7

A charge if 2 nC is placed 10cm to the right of a conducting sphere with a diameter of 2 cm. A charge of 5 nC is placed 10 nC to

the left of the same sphere. determine the charge at the center of the sphere.
Physics
1 answer:
SCORPION-xisa [38]3 years ago
3 0

Answer:

The charge at the center of the conducting sphere is zero.

Explanation:

A principle of conductor materials is that the electric field inside a conductor in electrostatic state is always zero. The gauss law says that the flux of a electric field in a closed surface is proportional to the charge enclosed by the surface. Then if the Electric field inside of a conductor is zero, imperatively the charge anywhere inside the conductor is zero too, so the charge at the center of the sphere is zero.

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The free-fall acceleration at the surface of planet 1 is 22 m/s^2. The radius and the mass of planet 2 are twice those of planet
algol13

Answer:

g₂ = 11 m/s²

Explanation:

The value of free-fall acceleration on the surface of a planet is given by the following formula:

g = \frac{Gm}{r^2}

where,

g = free-fall acceleration

G = Universal Gravitational Constant

m = mass of the planet

r = radius of planet

FOR PLANET 1:

g_1 = \frac{Gm_1}{r_1^2}\\\\\frac{Gm_1}{r_1^2} = 22 m/s^2 --------------------- equation (1)

FOR PLANET 2:

g_2 = \frac{Gm_2}{r_2^2}\\\\g_2 = \frac{G(2m_1)}{(2r_1)^2}\\\\g_2 = \frac{1}{2}\frac{Gm_1}{r_1^2}\\\\

using equation (1):

g_2 = \frac{g_1}{2}\\\\g_2 = \frac{22\ m/s^2}{2}

<u>g₂ = 11 m/s²</u>

8 0
3 years ago
A hydrogen bond forms by the electrostatic interaction of opposite charges in two molecules. If
Darya [45]

The force between the molecules involved in the bond is 6. 426 *10^-11 Newton

<h3>How to determine the force</h3>

Using the formula:

F = K[q1 x q2]/D^2

where K is coulombs constant =9 *10 ^9 Nm^2/C^2.

q1  and q2 = charges  =  1.60x10 -20C

d = distance between the charges = 2x10 -10 m

Substitute the values into the formula

F =  9 * 10^9\frac{ 1.60*10^ -20 *  1.60 *10^ -20}{2x10^ -10^{2} }

F = 9 *10^9\frac{2. 856* 10^-40}{4* 10^-20}

F = 9* 10^9 * 7. 14* 10^-21

F = 6. 426 * 10^-11 Newton

Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton

Learn more about electrostatic force here:

brainly.com/question/8424563

#SPJ1

5 0
2 years ago
A bell is rung. What best describes the density of air around the bell? The air density does not change. The air density increas
dezoksy [38]

I think the closest possible answer to this question is The air density increases and decreases repeatedly before returning to normal.Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
7 0
3 years ago
Read 2 more answers
Which particle would have the slowest rate of deposition? A.round particle B.very large particle C.particle with sharp ends D.pa
lisabon 2012 [21]

The particle with sharp ends have the slowest rate of deposition  

Answer: Option C  

<u>Explanation:</u>

          As per aerosol physics, deposition is a process where aerosol particles accumulate or settle on solid surfaces. Thereby, it reduces the concentration of particles in the air. Deposition velocity (rate of deposition) defines from F = vc, where v is deposition rate, F denotes flux density and c refers concentration.  

          Deposition velocity is slowest for particles of intermediate-sized particles because the frictional force offers resistance to the flow. Density is directly proportional to the deposition rate so clearly shows that high-density particles settle faster. Due to friction, round and large-sized particles deposit faster than oval/flattened sediments.  

3 0
3 years ago
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An object accelerates at 32 m/s² when a force of 71 N is applied to it. What is the object’s mass? show your work
amid [387]

Answer:

Its  answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

6 0
2 years ago
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