All categories

3 years ago

Two falling inflated balls of different masses land at the same time.

Physics

1 answer:

Mashcka [7]3 years ago

8 0

Answer:

true two falling inflated balls of different mass lands at the smae time because gravity acts to both in a same way

You might be interested in

What best describes the energy in a closed system at the beginning of a day and the energy at the end of the same day? Check all

jeka94

The second, fourth, and seventh answers apply. Energy in a closed system is conserved, but it can change form

6 0

3 years ago

Read 2 more answers

You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts,

g100num [7]

Answer:

$T = 29.66 ^o C$

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

$ms \Delta T = m' L$

so here we have

$0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)$

$T = \frac{2512.5}{0.220 \times 385}$

$T = 29.66 ^o C$

5 0

3 years ago

A plane wave with a wavelength of 500 nm is incident normally ona single slit with a width of 5.0 × 10–6 m.Consider waves that r

kaheart [24]

To solve this exercise it is necessary to use the concepts related to Difference in Phase.

The Difference in phase is given by

$\Phi = \frac{2\pi \delta}{\lambda}$

Where

$\delta =$ Horizontal distance between two points

$\lambda =$ Wavelength

From our values we have,

$\lambda = 500nm = 5*10^{-6}m$

$\theta = 1\°$

The horizontal distance between this two points would be given for

$\delta = dsin\theta$

Therefore using the equation we have

$\Phi = \frac{2\pi \delta}{\lambda}$

$\Phi = \frac{2\pi(dsin\theta)}{\lambda}$

$\Phi = \frac{2\pi(5*!0^{-6}sin(1))}{500*10^{-9}}$

$\Phi= 1.096 rad \approx = 1.1 rad$

Therefore the correct answer is C.

6 0

3 years ago

g a horizontal wheel of radius is rotating about a vertical axis. What is the magnitude of the resultant acceleration of a bug t

mihalych1998 [28]

Answer:

a = w² r

Explanation:

In this exercise, indicate that the wheel has angular velocity w, the worm experiences the same angular velocity if it does not move, and has an acceleration towards the center of the circle, according to Newton's second law, called the centripetal acceleration.

a = v² / r

angular and linear variables are related

v = w r

we substitute

a = w² r

where r is the radius of the wheel

4 0

3 years ago

in the circuit diagram, what does the symbol made of two long lines and two short likes with a positive and a negative sign at e

IrinaVladis [17]

It is a battery (the long and short lines represent 2 cells)

7 0

3 years ago