Answer:
F = - k (x-xo) a graph of the weight or applied force against the elongation obtaining a line already proves Hooke's law.
Explanation:
The student wants to prove hooke's law which has the form
F = - k (x-xo)
To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.
Now for a series of known masses let's get them one by one and measure the spring elongation, building a table of weight vs elongation,
we must be careful when hanging the weights so as not to create oscillations in the spring
we look for the mass of each weight
W = mg
m = W / g
and we write them in a new column, we make a graph of the weight or applied force against the elongation and it should give a straight line; the slope of this line is sought, which is the spring constant.
The fact of obtaining a line already proves Hooke's law.
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that the friction force on two boxes is given as
Now we know by Newton's II law
so we have
Part b)
For block B we know that net force on it will push it forward with same acceleration so we have
Part c)
If Alex push from other side then also the acceleration will be same
So for box B we can say that Net force is given as
What is the longest the bolt can be and still be acceptable
