(a) 1800 N
The equation of the forces along the vertical direction is:

where
is the component of the applied force along the vertical direction
N is the normal force on the sled
mg is the weight of the sled
Substituting:
F = 1210 N
m = 246 kg

We find N:

(b) 0.580
The equation of the forces along the horizontal direction is:

where
is the horizontal component of the push applied by the mule
is the static frictional force
Substituting:
F = 1210 N
N = 1800 N

We find
, the coefficient of static friction:

(c) 522 N
In this case, the force exerted by the mule is

So now the equation of the forces along the horizontal direction can be written as

where

and
is the new frictional force, which is different from part (b) (because the value of the force of friction ranges from zero to the maximum value
, depending on how much force is applied in the opposite direction)
Solving the equation,

Answer:
v= 3.18 m/s
Explanation:
Given that
m= 150 g = 0.15 kg
M= 240 g = 0.24 kg
Angular speed ,ω = 150 rpm
The speed in rad/s


ω = 15.7 rad/s
The distance of center of mass from 150 g

r= 20.30 cm
The speed of the mass 150 g
v= ω r
v= 20.30 x 15.7 cm/s
v= 318.71 cm/s
v= 3.18 m/s
The simplest compound of hydrocarbon is methane
- The formula is CH_4
- It belongs to alkane group and has single bonds.
The electron structure attached
Answer:
C
Explanation:
they are still in the same plane witch means they going the same speed