Which term is defined as an investigative process that recognizes that scientific concepts and

pantera1 [17]

6. F- DNA
7. C
8. G
9. D
I believe these are correct, hope this helps.

7 0

3 years ago

Suppose we wish to use a 6.0 m iron bar to lift a heavy object by using it as a lever. If we place the pivot point at a distance

Ber [7]

Answer:

The maximum load that this person is able to lift is 34.3 N

Explanation:

Applying the balancing torque, the expression is equal:

F₁L₁ = F₂L₂

$mgL_{1} =F_{2} L_{2}$

Where

g = 9.8 m/s² = gravity

L₁ = 0.8 m

F₂ = 527 N

L₂ = 6 - 0.8 = 5.2 m

Replacing and clearing the mass m:

$m=\frac{F_{2}L_{2} }{gL_{1} } =\frac{527*5.2}{9.8*0.8} =3.5kg$

The maximum load that this person is able to lift is:

F = m * g = 3.5 * 9.8 = 34.3 N

8 0

3 years ago

An object moves at 60 m/s in the +x direction. As it passes through the origin it gets a 4.5 m/s^2 acceleration in the -x direct

Brut [27]

Answer:

a) After 26.67 seconds it returns back to the origin

b) Velocity when it returns to the origin = 60 m/s in the -x direction

Explanation:

a) Let the starting position be origin and time be t.

After time t displacement, s = 0 m

Initial velocity, u = 60 m/s

Acceleration, a = -4.5 m/s²

We have equation of motion s = ut + 0.5 at²

Substituting

s = ut + 0.5 at²

0 = 60 x t + 0.5 x (-4.5) x t²

2.25t² - 60 t = 0

t² - 26.67 t = 0

t (t-26.67) = 0

t = 0s or t = 26.67 s

So after 26.67 seconds it returns back to the origin

b) We have equation of motion v = u + at

Initial velocity, u = 60 m/s

Acceleration, a = -4.5 m/s²

Time , t = 26.67

Substituting

v = 60 - 4.5 x 26.67 = -60 m/s

Velocity when it returns to the origin = 60 m/s in the -x direction

4 0

3 years ago

Four uniform objects having the same mass and diameter are released simultaneously from rest at the same distance above the bott

Jet001 [13]

The one with the majority of its mass furthest away from its center will reach the bottom last. The thin walled cylinder has all of its mass at the edge of itself, meaning its mass is the furthest from its center. If we take a look at the solid cylinder, it has some mass at its edge, but it also has a lot of mass very close to its center so it will roll faster than the thin walled cylinder. And the thin walled cylinder will be slower than the normal hollow cylinder because even though the hole cylinder doesn't have any mass at its center it does have some mass closer to its center than the thin walled cylinder.

So the last one to reach the bottom is the thin walled cylinder.

8 0

3 years ago

A double-slit arrangement produces bright interference fringes for sodium light ( λ = 603 nm) that are angularly separated by 0.

ohaa [14]

Answer:

θ for water = 0.3684°

Explanation:

given data

wavelength λ = 603 nm

angle θ = 0.49°

index of refraction n = 1.33

to find out

angular fringe separation

solution

we know that double slit interference is here

m λ = d sin(θ) .................1

so for air it will be

m λ(air) = d sin(θ)air ...........2

and for water it will be

m λ(water) = d sin(θ)water .............3

now we take here ratio of equation 2 and 3

$\frac{\lambda (water)}{\lambda(air)}$ = $\frac{sin(\Theta)water}{sin(\Theta)air}$

and

ratio of wavelength is = $\frac{1}{n}$

ratio of wavelength = $\frac{1}{1.33}$

ratio of wavelength = 0.75187

so

sin(θ)water = sin(θ)air (0.75187)

sin(θ)water = sin(0.49) (0.75187)

sin(θ)water = 0.006429

so (θ)water is

(θ)water = 0.3683°

we notice here that by using small angle formula

we have approximate sin(θ) = θ

so θ for water is = $\frac{\Theta }{n}$

θ for water = $\frac{0.49}{1.33}$

θ for water = 0.3684°

7 0

3 years ago