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Alex787 [66]
3 years ago
8

The environmental and economic benefits of hydroelectricity, giving examples from the case studies and

Physics
2 answers:
Anika [276]3 years ago
8 0

Answer:

  • <u>The issue regarding finding new sources of energy:</u>

Human beings are always in search to find more clean and better resources for developing the different mechanisms( mechanical processes) and improving the quality of products inside the different industries. As, there are the conventional form of energy resources (i.e petroleum and coal) for driving the industrial processes. Because, the raw materials used in providing the required level of energy for carrying out different industrial processes are more harmful for both the environment and human health.

  • <u>The solution for the problem:</u>

As, we require more efficient and convenient energy resources like the hydroelectricity. The hydroelectricity was introduced more then a century ago for providing us with more clean energy resources for improving our lives and different industrial mechanisms across the globe.

  • <u>Implementation of the idea:</u>

There are a number of ideas present for the implementation of the hydroelectric power generating structures inside a region. There are a number of advanced and high-tech materials and machines present for the building up of the various structures to generate electric power for domestic and industrial uses.  There are various laws and principles which govern the energy conservation and its transmission to the specified destination.

  • <u>Conclusion:</u>

As it would benefit the country's development both economically and socially. As it will result in a more clean environment for all the being and to have a more clean and advanced form of environment to live in.

vredina [299]3 years ago
3 0

Answer:

Review the explanation.

Explanation:

Hydropower does not generate CO2 emissions, therefore it is not a factor in the generation of global warming. The initial investment of this type of projects in construction is large but this investment can be recovered in the future, since the system guarantees reliability in the supply of energy. It generates employment as technical and engineering personnel are needed for the operation of each of the equipment that is part of the hydroelectric plant.

As for the defects, is that most hydropower should be located near rivers, therefore to access the construction of this project must cut trees and remove animals from their natural habitat.

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skelet666 [1.2K]

Answer:

"The tendency of an object to resist changes in its state of motion varies with mass. Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion."

Explanation:

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3 years ago
Philosophy:The Big Picture Unit 7
zhenek [66]

Answer:

B

Explanation:

If you cross of what you don't think are the answers then it makes it easier to narrow it down to what the answers are.

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4 0
3 years ago
Two lightbulbs have powers P1 and P2 when separately connected across an ideal battery with potential difference ΔV. The bulbs a
jarptica [38.1K]

Answer:

P'=\dfrac{P_1P_2}{P_1+P_2}

Explanation:

Lets take

Resistance of bulb 1 =R₁

Resistance of bulb 2 =R₂

As we know that power P

P= ΔV²/R

Given that voltage difference is same for both bulbs

So

P₁R₁= ΔV²       --------1

P₂R₂= ΔV²   -----------2

When these resistance are connected in series then equivalent resistance R

R=R₁+ R₂

The new power P'

P'=ΔV²/R

P'R=ΔV²   ------3

From equation 1 ,2 and 3

P'(R₁+ R₂) = ΔV²

P'\left(\dfrac{\Delta V^2}{P_1}+\dfrac{\Delta V^2}{P_2}\right)=\Delta V^2

P'=\dfrac{P_1P_2}{P_1+P_2}

6 0
3 years ago
What is the meaning of velocity?
Nutka1998 [239]
It's the speeding of an object given in a specific direction.

Average Velocity = displacement / time
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4 0
3 years ago
Read 2 more answers
A block with mass m = 0.200 kg is placed against a compressed spring at the bottom of a ramp that is at an angle of 53.0∘ above
Murljashka [212]

Answer:

0.566\; \rm N (assuming that while the block is moving, the friction on the block is constant.)

Explanation:

The mechanical energy of a system is the sum of its:

  • elastic potential energy,
  • gravitational potential energy, and
  • kinetic energy.

Friction does work on the block as the block moves up the ramp. The amount of energy that the block-string system has lost would be equal in size to the work that friction has done on the block. The size of the friction on the block could thus be computed.

Before this block was released, the block-spring system has no kinetic energy because there was no movement. Assume that the system has no gravitational potential energy at that moment, either. The only type of mechanical energy in this system at that moment would be elastic potential energy: 8\; \rm J according to the question.

The question states that the ramp is 53.0^\circ above horizontal. Therefore, after the block has traveled 3.00\; \rm m (along the ramp,) the height of this block would have increased by \Delta h = 3.00\; \rm \sin\left(53^\circ\right) \approx 2.39591\; \rm m. Calculate the corresponding gain in gravitational potential energy:

\begin{aligned}& m \cdot g \cdot \Delta h\\ &\approx 0.200\; \rm kg& \\\ &\quad\times 9.81\; \rm N \cdot kg^{-1} \\ &\quad \times 2.39591\; \rm m \\ &\approx 4.70077\; \rm J\end{aligned}.

On the other hand, the question states that the speed of the block (m = 0.200\; \rm kg) at that moment is v = 4.00\; \rm m \cdot s^{-1}. Calculate the corresponding kinetic energy:

\begin{aligned}& \frac{1}{2}\, m \cdot v^{2} = 1.6\; \rm J \end{aligned}.

Because the block was already released, there should be no elastic potential energy in the spring.

Hence, the mechanical of the block-spring system would be approximately 4.70077\; \rm J+ 1.6\; \rm J \approx 6.30077\; \rm J.

Approximate the amount of mechanical energy that is lost:

8\; \rm J - 6.30077\; \rm J \approx 1.69923\; \rm J.

In other words, when applied over 3\; \rm m, the friction on this block would do approximately 1.69923\; \rm J of work. Approximate the size of that friction:

\begin{aligned}F &= \frac{W}{s} \\ &\approx \frac{1.69923\; \rm J}{3.00\; \rm m}\approx 0.566\; \rm N\end{aligned}.

3 0
3 years ago
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