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ki77a [65]
3 years ago
12

An astronaut orbits planet Y in her spaceship. To remain in orbit at 410km above the planet's center, she maintains a speed of 6

8 m/s. What is the mass of planet Y? Note: the constant of universal gravity (G) equals 6.674 × 10-11 N ⋅ m2/kg2.
Physics
1 answer:
choli [55]3 years ago
3 0
Formula for orbital speed, v =  √(GM/R)

Where G is the universal gravitational constant, M = Central Mass,

R = Distance between centers of Mass.

Given.  v = 68 m/s, M = ? , R = 410 km = 410000 m., G = 6.674 * 10⁻¹¹ Nm²/kg²

68 = √(GM/R)

68 = √(6.674 * 10⁻¹¹ * M/410000)

68² =  (6.674 * 10⁻¹¹ * M)/410000

(68²  * 410000) / 6.674 * 10⁻¹¹    = M

2.84 × 10¹⁹    = M

Mass of Planet Y =  2.84 × 10¹⁹ kg
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sleet_krkn [62]

Answer:

v = \left[\begin{array}{c}0.66&0\end{array}\right]m/s

Explanation:

The position vector r of the bug with linear velocity v and angular velocity ω in the laboratory frame is given by:

\overrightarrow{r}=vtcos(\omega t)\hat{x}+vtsin(\omega t)\hat{y}

The velocity vector v is the first derivative of the position vector r with respect to time:

\overrightarrow{v}=[vcos(\omega t)-\omega vtsin(\omega t)]\hat{x}+[vsin(\omega t)+\omega vtcos(\omega t)]\hat{y}

The given values are:

t=\frac{x}{v}=\frac{14}{3.8}=3.7 s

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8 0
3 years ago
A block of mass 500g is pulled from rest on ahorizontal frictionless bench by a steady force F and travels 8m in 2s find the acc
Korvikt [17]

<u>We are Given:</u>

Mass of the block (m) = 500 grams or 0.5 Kg

Initial velocity of the block (u) = 0 m/s

Distance travelled by the block (s) = 8 m

Time taken to cover 8 m (t)= 2 seconds

Acceleration of the block (a) = a m/s²

<u>Solving for the acceleration:</u>

From the seconds equation of motion:

s = ut + 1/2* (at²)

<em>replacing the variables</em>

8 = (0)(2) + 1/2(a)(2)²

8 = 2a

a = 4 m/s²

Therefore, the acceleration of the block is 4 m/s²

3 0
2 years ago
Can someone help me?!!!!!
ladessa [460]

Answer:

magnitude: 21.6; direction: 33.7 degrees

Explanation:

When we multiply a vector by a scalar, we have to multiply each component of the vector by the scalar number. In this case, we have

vector: (-3,-2)

Scalar: -6

so the vector multiplied by the scalar will have components

(-3\cdot (-6), -2 \cdot (-6))=(18,12)

The magnitude is given by Pythagorean's theorem:

m=\sqrt{18^2+12^2}=21.6

and the direction is given by the arctan of the ratio between the y-component and the x-component:

\theta = tan^{-1} (\frac{12}{18})=33.7^{\circ}

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3 years ago
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balu736 [363]

Answer: a and d

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D.) the metal tools the worker uses

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