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inn [45]
3 years ago
8

A soccer player practices kicking the ball into the goal from halfway down the field the time it takes for the ball to get to th

e goal from the time it was kicked averages about 3 seconds the soccer field is 90 meters long the player wants to know the average velocity of the ball is there enough information to calculate this ?
Chemistry
2 answers:
Nataliya [291]3 years ago
5 0
Velocity = 15 m/s

90/2 = 45 m
45/3 (seconds to reach) = 15 m 



RSB [31]3 years ago
5 0

On the test the answer is Yes, displacement is 45 meters, elapsed time is three seconds, and the direction is toward the goal.

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Elena L [17]

Answer:

Correct option: Vapor pressure increases with temperature

Explanation:

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Kinetic energy of molecule depends on the temperaure of sample or molecules when temperature is increased then its kinetic energy also increased and as kinetic energy increases then the chances of molecule going into vapour phase increases thereby increasing the vapour pressure.

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4 0
3 years ago
What happens to the conductivity of water when an acid is dissolved in it for bases?
Degger [83]
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8 0
3 years ago
The properties of two elements are listed below. Element Atomic radius (pm) Ionic radius (pm) First ionization energy (kJ/mol) E
Sedbober [7]

Answer:

K will give up an electron more easily than Br.

Explanation:

Electronegativity of an element is a property that combines the ability of its atom to lose and gain electrons.

The lower the electronegativity value, the more electropositive an element is and the more readily it loses electrons.

From the data given, we see that Br has an E.N value of 3.0 and K has an E.N value of 0.82.

Therefore, Br is highly electronegative and it is able to attract electrons to itself whereas K has a low E.N value. K will give up electrons more readily.

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5 0
3 years ago
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Lunna [17]

Answer:

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Explanation:

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He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

6 0
3 years ago
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I don't understand your question, but I think that would help.

4 0
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