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Setler [38]
3 years ago
15

What is the definition of the fugacity coefficient for a pure component, and its condition at the ideal gas state?

Chemistry
1 answer:
inn [45]3 years ago
4 0

Answer:

For thermodynamics the fugacity (fi) of a non ideal gas is defined as the product between the activity (ai) of the gas and 1 bar of pressure.

Explanation:

For thermodynamics the fugacity (fi) of a non ideal gas is defined as the product between the activity (ai) of the gas and 1 bar of pressure.

f_{i} = a_{i} x 1bar

Also, in a gas mixture the fugacity (fi) of every component of the mixture is define by a coefficient of fugacity (Фi) multiplied by the partial pressure of the gas (Pi) :

f_{i} = Ф_{i} x P_{i}

The coefficient of fugacity (Фi) is a measure of the deviation from the ideality of the gas. Thus, for an ideal gas Фi = 1 and the fugacity (fi) turns equal to partial pressure:

If Фi = 1  ⇒  f_{i} =P_{i}

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The answer is False. the amplitude shows how high or low something is
6 0
3 years ago
Why should you be careful when you heat your NaCl solution to evaporate the water?
ivolga24 [154]

Answer & Explanation:

  • If we heat the NaCl solution strongly, it boils and moves vigorously causing some of the solution to get out of the container.
  • This will cause loss of NaCl in the amount that get out of the container.
  • So, this affect the yield of the obtained NaCl after water evaporation.
7 0
3 years ago
What would be the mass of 9.03*10^21 molecules of hydrobromic acid
Fynjy0 [20]

Answer:

2.11 g hydrobromic acid (correct to 3SF)

Explanation:

Molecular formula of hydrobromic acid = C2H5BrO2

mass of C2H5BrO2 = 140.96g

Beginning with what we're given, 9.03*10^21 we then make a conversion by using Avegadro's number which is 6.02*10^23 per mole (Oct. 23 at 6:02 am is national mole day :) Then, we need to convert out of moles, 140.96g hydrombromic acid per mole.

It looks like this:

9.03*10^21 molecules • (1 mol C2H5BrO2 / 6.02*10^23 molecules) • (140g C2H5BrO2 / 1 mol) = 2.1144 g C2H5BrO2

3 0
3 years ago
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
What is the volume of 2 mol of chlorine gas at STP?<br> 2.0 L<br> 11.2 L<br> 22.4 L<br> 44.8 L
nirvana33 [79]

Answer:

44.8 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At Standard temperature and pressure (STP);

P = 1 atm

T = 273K

Hence, when n = 2moles, the volume of the gas is:

Using PV = nRT

1 × V = 2 × 0.0821 × 273

V = 44.83

V = 44.8 L

7 0
3 years ago
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