The final temperature of the mixture will be <u>30⁰C</u>
Since it is given that 50 gms of water at 20 ⁰ C and 50 gms of water at 40⁰ C are mixed. Since the masses of the liquid at different temperatures are the same, the answer is very easy and simple: average of 20⁰C and 40⁰C. that is 30⁰C.
<em>the final temperature of the mixture = </em>
<em> = [ m1 * T1 + m2 * T2 ] / (m1 + m2)</em>
<em> = [ 50 gms * 20⁰ C + 50 gms * 40⁰C ] / (50+50)</em>
<em> </em><em> = 3,000 / 100 = </em><u><em>30⁰C</em></u>
In chemistry, we define the temperature of a substance as the average kinetic power of all of the atoms or molecules of that substance. No longer do all of the debris of a substance have identical kinetic strength. At any given time, the kinetic energy of the debris may be represented by means of a distribution.
Temperature performs a vital function in-hospital treatment (both humans and animals), food, beverages, and agriculture. Our average fitness is regularly reliant upon the temperature in lots of methods as nicely.
The SI unit of temperature as consistent with the global system of devices is Kelvin.
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Answer:
∇T = 51.68°C
Explanation:
Mass = 150g
Heat Energy (Q) = 1.0*10³J
Change in temperature ∇T = ?
Q = mc∇T
Q = heat energy
M = mass
C = specific heat capacity of the gold = 0.129j/g°C
∇T = change in temperature
Q = Mc∇T
1.0*10³ = 150 * 0.129 * ∇T
1000 = 19.35∇T
Solve for ∇T
∇T = 1000 / 19.35
∇T = 51.679°C = 51.68°C
The change in temperature of gold was 51.68°C
Answer:the first column has one valance electron the second has 2 and so on.
The only exception is helium that has 2.
Explanation:
Remark
The question with these kind of problems is "Which R do you use?" That's where dimensional analysis is so handy. You must look at the units of the givens and choose your R accordingly. You'll see how that works in a moment.
You need to list the givens along with their units and in this case the property you want to solve for. You need all that to determine the R value
Givens
n = 0.25 moles
T = 35°C = 35 + 273.15 = 308.15°K
V = 6.23 L
Pressure = P in kPa
Which R
The units of the R you want has to have units of moles, kPa, °K and liters
The R that you want is 8.314
<em><u>Formula</u></em>
PV = nRT
P 6.23 = 0.25 * 8.314 * 308.15 Combine the left
P*6.23 = 640.5
P = 640.5/6.23 = 102.81 The answer should be 100 kpA of 1.0 * 10^2 kPa
because the number of moles has only 2 sig digs.
But if sig digs are not a problem 102.8 is likely close enough.
Second Question
You are going to have to clean up the numbers. I think I've got only 1 chance at this. The partial pressures of the 2 gases will add up to the total pressure. So the total pressure was 100 approx and the water vapor was 3.36 kPa. The difference is
Total = air + water vapor
100.18 = air + 3.36 about Subtract 3.36 from both sides.
100.18 - 3.36 = 96.82 about. Pick the answer that is closest to that. I'll clean up the numbers if I can.
Answer C