Due to the ideal gas law, we have an equation: PV=nRT. So when the pressure and amount of gas are constant, V1/T1=V2/T2. Temperature using the unit of K. So the answer is 535*319/296=576.6 mL.
Explanation:
13. 8,448 = 8,450 (round up, 8 more than 5)
14. 89.32 = 89.3 (round down, 2 less than 5, 0 is not needed)
15. 0.05678 = 0.0568 (round up, 8 more than 5, 0 in front are not significant)
In a displacement reaction, a more reactive element replaces a less reactive element from a compound. In a double displacement reaction, two atoms or a group of atoms switch places to form new compounds.
Explaination:
Displacement chemical reaction :
A displacement reaction is the one wherein the atom or a set of atoms is displaced by another atom in a molecule. For instance, when iron is added to a copper sulphate solution, it displaces the copper metal.
Fe + CuSO4 → FeSO4 + Cu. When zinc is added to a copper sulphate solution, it displaces the copper metal. ...
Zn + CuSO4 → ZnSO4 + Cu.
etc.
Double Displacement Chemical Reaction :
Double displacement reactions take place mostly in aqueous solutions wherein the ions precipitate and exchange of ions takes place. For example, when a solution of barium chloride is mixed with sodium sulphate, a white precipitate of barium sulphate is formed rapidly. These reactions are ionic in nature.
Here are some examples of double displacement reaction: AgNO 3 + NaCl → AgCl + NaNO.
2NaCl + CaSO4 → Na2SO4+ CaCl.
H2SO4 + 2LiOH ⇌ Li2SO4 + 2H2O.
Answer:
760 mm of Hg
Explanation:
If the gases A , B and C are non reacting , then according to <u>Dalton's </u><u>Law </u><u>of</u><u> </u><u>Partial </u><u>Pressure</u> the total pressure exerted is equal to sum of individual partial pressure of the gases .
If there are n , number of gases then ,
Here ,
- Partial pressure of Gas A = 400mm of Hg
- Partial pressure of Gas B = 220 mm of Hg
- Partial pressure of Gas C = 140mm of Hg
Hence the total pressure exerted is ,
Substitute ,

Add ,

<u>Hence</u><u> the</u><u> </u><u>total</u><u> pressure</u><u> exerted</u><u> by</u><u> the</u><u> </u><u>gases </u><u>is </u><u>7</u><u>6</u><u>0</u><u> </u><u>mm </u><u>of </u><u>Hg</u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>
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