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Ronch [10]
3 years ago
11

The rate of this reaction is markedly increased if a small amount of sodium iodide is added to the reaction mixture. The sodium

iodide is not consumed by the reaction and is therefore considered to be a catalyst. Explain how the presence of iodide can speed up the rate of the reaction.
Chemistry
1 answer:
pantera1 [17]3 years ago
8 0

Answer:

See explanation

Explanation:

SN2 reaction is a synchronous reaction in which the leaving group departs as the nucleophile is being attached to the substrate in a single step. This makes it imperative to use a good leaving group when carrying out an SN2 reaction such as the one shown in the question.

The addition of a small amount of NaI acts as a sort of external nucleophile which assists the departure of the leaving group thereby enabling the reaction to proceed faster. This occurs because the iodide ion is very good leaving group.

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A student predicts that a solution of ethanol (C2H5OH) and water will have a lower density at room temperature than that of pure
ohaa [14]

Answer:

It would probably be, something that can take up moisture to test it.

Explanation:

(to see if it can evaporate)

4 0
3 years ago
Read 2 more answers
Acetic acid (HC2H3O2, Ka=1.8x10^-5) is a weak acid. Calculate the pH of an aqueous solution of .25M acetic acid.
tensa zangetsu [6.8K]

Answer: The pH of an aqueous solution of .25M acetic acid is 2.7

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.25 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.25\times \alpha)^2}{(0.25-0.25\times \alpha)}

(\alpha)=0.0084

[H^+]=c\times \alpha

[H^+]=0.25\times 0.0084=0.0021

Also pH=-log[H^+]

pH=-log[0.0021]=2.7

Thus pH is 2.7

5 0
3 years ago
How does electronegativity affects the type of intramolecular bond that is formed between atoms
Effectus [21]

Answer:

If the electronegativity difference between bonded atoms are too much high ionic bonds are formed if the electronegativity diference is 0.4 or less than 0.4 non polar covalnet bond formed the difference greater than 0.4 polar covalent bond formed.

Explanation:

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

5 0
3 years ago
What is the mass of 99.0 L of NO2 at STP
Mariana [72]
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3 0
4 years ago
Name the following cycloalkane:
KonstantinChe [14]

B is the correct answer

8 0
3 years ago
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