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dlinn [17]
3 years ago
5

What is the concentration (m) of ch3oh in a solution prepared by dissolving 16.8 g of ch3oh in sufficient water to give exactly

230 ml of solution?
Chemistry
1 answer:
Natalija [7]3 years ago
5 0

The Molarity concentration is expressed in units of moles / L. So let us first determine the number of moles of CH3OH, and then divide that amount by the total volume of 0.230 L of solution.<span>

<span>To determine the number of moles of CH3OH, divide the weight in grams of CH3OH by the molecular weight of CH3OH: (MW of CH3OH = 32 g / mol)</span>

number of moles = 16.8 g / (32 g / mol)</span>

number of moles = 0.525 mol CH3OH <span>

Then we calculate for molarity:</span>

Molarity = 0.525 mol CH3OH / .230 L

Molarity = 2.2826 mol / L

<span>Molarity = 2.28 M</span>

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