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masya89 [10]
3 years ago
13

What is homeostasis?

Chemistry
2 answers:
Alexandra [31]3 years ago
5 0

Answer:

""the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes.""

Explanation:

ipn [44]3 years ago
5 0

Answer:the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes.

Explanation:

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Which molecule contains the smallest number of hydrogen atoms? A) N2H4. B) Al(OH) 3. C) (NH4) 2SO4. D) NH4NO3.
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The molecule that contains the fewest number of Hydrogen atoms would be B. Al(OH)3. It only has 3 Hydrogen atoms.
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pentagon [3]

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the answer is d.

Explanation:

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3 years ago
Which of the following is required for a liquid to become a solid one
tino4ka555 [31]

Answer:The process of a solid becoming a liquid is called melting

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8 0
3 years ago
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In this experiment, you are given 3 unknown metals and will determine their identities by finding their densities. The possible
Hitman42 [59]

Answer:

Explanation:

This question is a practical question that needs to be practiced in a lab. However, the guide below will assist in answering the question.

Let's assume our unknown metals are X, Y and Z. The unknown metals will be weighed using a weight boat on an electronic balance. Hence, the mass of the weight boat will have to be measured if you do not wish to "tare" the balance when the weight boat is on it - the instruction in the question prefers the former.

Assuming the mass of the weight boat is measured to be 10g (and then recorded), the unknown is added to it until the balance reads 60g.

Hence,

The total mass recorded on the balance = the mass of the weight boat + 50g of the unknown sample.

When the unknown sample is then poured into the 10 ml of water in the 25 ml graduated cylinder, the volume of water will rise. The final volume of the water must be recorded in order to calculate the change in volume.

change in volume = Final volume recorded - 10 ml (volume of water before the sample was added)

Density of the unknown solid = mass of unknown solid (50 g) ÷ change in volume

This process is done three times (and all values recorded) for each metal (X, Y and Z). And the process is also done (three times with all values recorded) with different masses of 75 g and 100 g of the unknown sample.

In order to calculate the average density of each unknown metal, the following can be done.

The average density of unknown metal X of 50g (assuming it's DX₁) = (density obtained after first experiment + density obtained after second experiment + density obtained after third experiment)/3

The average density of unknown metal X of 75g (assuming it's DX₂) = (density obtained after first experiment + density obtained after second experiment + density obtained after third experiment)/3

The average density of unknown metal X of 100g (assuming it's DX₃) = (density obtained after first experiment + density obtained after second experiment + density obtained after third experiment)/3

The average density of metal X = (DX₁ + DX₂ + DX₃)/3

The same calculations (above) is repeated for metals Y and Z.

From the question, platinum has the highest density, followed by rhodium and then silver. Hence, after the experiments and then the calculations, <u>the unknown metal with the highest average density will be assumed to be platinum and the next one will be assumed to be rhodium while the one with the least average density will be assumed to be silver</u>.

8 0
3 years ago
A liquid mixture contains 1 kg of water, 1.9 lb of ethanol, and 4.6 lb of methyl acetate. What is the weight fraction of ethanol
slamgirl [31]

<u>Answer:</u> The weight fraction of ethanol in the mixture is

<u>Explanation:</u>

We are given:

Mass of water = 1 kg = 2.205 lb   (Conversion factor:  1 kg = 2.205 lb)

Mass of ethanol = 1.9 lb

Mass of ethyl acetate = 4.6 lb

Mass of mixture = [2.205 + 1.9 + 4.6] = 8.705 lb

To calculate the percentage composition of ethanol in mixture, we use the equation:

\%\text{ composition of ethanol}=\frac{\text{Mass of ethanol}}{\text{Mass of mixture}}\times 100

Mass of mixture = 8.705 lb

Mass of ethanol = 1.9 lb

Putting values in above equation, we get:

\%\text{ composition of ethanol}=\frac{1.9lb}{8.705lb}\times 100=21.8\%

Hence, the weight fraction of ethanol in the mixture is 21.8 %

4 0
3 years ago
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