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OleMash [197]
3 years ago
14

calculate the distance in km that alex can run in 2.0 hours if she maintains the constant average speed of 8.00 km/h

Physics
1 answer:
Tema [17]3 years ago
4 0
16 kilometers is the answer i came up with. hope this helps.
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34. A train, starting from rest, accelerates along the platform at a uniform rate of 0.6 m/s2. A passenger standing on the platf
ira [324]

Answer:

4.08 s

Explanation:

Let the passenger took "t" time to catch the train

so in this case the total distance moved by the train + 5 m = total distance moved by the passenger

so we will have

distance moved by train is given as

d_1 = \frac{1}{2}(0.6) t^2

also the distance moved by passenger

d_2 = \frac{1}{2}(1.2) t^2

so we will have

d_1 + 5 = d_2

0.3 t^2 + 5 = 0.6 t^2

0.3 t^2 = 5

t = 4.08 s

3 0
3 years ago
When a magnetic field is first turned on, the flux through a 20-turn loop varies with time according to Φm=5.0t2−2.0t, where Φm
goldfiish [28.3K]

Answer:

A) ( - 200t + 40 ) volts

B)  b) anticlockwise ,  c) anticlockwise , d) clockwise ,  e) clockwise

Explanation:

Given data:

magnetic flux (Φm) = 5.0t^2 − 2.0t

number of turns = 20

<u>a) determine induced emf </u>

E = - N \frac{d\beta }{dt}

  =  - N ( 10t - 2 ) = - 20 ( 10t - 2 )

  =  - 200t + 40  volts

<u>b) Determine direction of induced current </u>

i) at t = 0

 E = - 0 + 40  ( anticlockwise direction )

ii) at t = 0.10

E = -20 + 40 =  20 ( anticlockwise direction )

iii) at t = 1

E = - 200 + 40 = - 160 ( clockwise direction)

iv) at t = 2

E = -400 + 40 =  - 360 ( clockwise direction )

8 0
2 years ago
A cheetah runs with a constant speed of 8 m/s. How far has the cheetah gone after 25 seconds?
Radda [10]
Multiply 25 * 8 = 200
So the cheetah has gone 200 miles in 25 seconds
7 0
3 years ago
Read 2 more answers
How far is the Earth from the Sun?
ohaa [14]

Answer:93.431 million mi

Explanation:

google lol

4 0
3 years ago
Read 2 more answers
Suppose a 1.2 m antenna is installed on top of a building that is 225 m tall,
vazorg [7]

Answer: 226.2 m

Explanation:

If we want to find the new total height H of the building, we have to add to its initial height h_{B}=225m the height of the antenna h_{A}=1.2m, as follows:

H=h_{B}+h_{A}

H=225m+1.2m

Then:

H=226.2m This is the new total height of the building.

7 0
3 years ago
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