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iogann1982 [59]
3 years ago
11

The points plotted on a graph represent the actual data recorded by an experiment.

Physics
2 answers:
aleksandr82 [10.1K]3 years ago
4 0
True. Depending how accurate the graph is plotted
Ira Lisetskai [31]3 years ago
3 0
True.. At the same time it depends on how accurate the experiment is done
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A fly sits on a potter's wheel 0.30 m from its axle. The wheel's rotational speed decreases from 4.0 rad/s to 2.0 rad/s in 5.0 s
earnstyle [38]

Answer:

0.4rad/s²

Explanation:

Angular acceleration is the time rate of change of angular velocity . In SI units, it is measured in radians per second squared (rad/s²)

w1 = 4rad/s, w2 =2rad/s, t = 5sec, r = 0.30m

a = ∆w/t

a = (w2 - w1)/t

a = (2 - 4)/5 = -2/5 =

a = - 0.4rad/s²

The -ve sign indicates a deceleration in the motion

Good luck

3 0
3 years ago
A motor has an armature resistance of 3.75 Ω . Part A If it draws 9.10 A when running at full speed and connected to a 120-V lin
bulgar [2K]

Back emf is 85.9 V.

<u>Explanation:</u>

Given-

Resistance, R = 3.75Ω

Current, I = 9.1 A

Supply Voltage, V = 120 V

Back emf = ?

Assumption - There is no effects of inductance.

A motor will have a back emf that opposes the supply voltage, as the motor speeds up the back emf increases and has the effect that the difference between the supply voltage and the back emf is what causes the current to flow through the armature resistance.

So if 9.1 A flows through the resistance of 3.75Ω then by Ohms law,

The voltage across the resistance would be

v = I x R

  = 9.1 x 3.75

  = 34.125 volts

We know,

supply voltage = back emf + voltage across the resistance

By plugging in the values,

120 V = back emf + 34.125 V

Back emf = 120 - 34.125

                = 85.9 Volts

Therefore, back emf is 85.9 V.

4 0
3 years ago
A 2.0-cm-diameter, 15-cm-long solenoid is tightly wound with one layer of wire. A 2.5 A current through the wire generates a 3.0
sweet [91]

Answer:

d = 1.047 mm

Explanation:

given,

diameter of the wire = 2.0-cm

length of solenoid = 15 cm = 0.15

Current in the wire = I = 2.5 A

magnetic field = B = 3.0 mT

Magnetic field inside the solenoid

        B = \dfrac{\mu_0 N I}{L}

        B = \dfrac{\mu_0 N I}{L}

               N x d = l

        N = \dfrac{l}{d}

        B = \dfrac{\mu_0 \dfrac{l}{d} I}{L}

        3 \times 10^{-3} = \dfrac{4\pi \times 10^{-7}\times \dfrac{0.15}{d}\times 2.5}{0.15}

        0.45 \times 10^{-3}\ d = 4\pi \times 10^{-7}\times 0.15\times 2.5

        \ d = \dfrac{4\pi \times 10^{-7}\times 0.15\times 2.5}{0.45 \times 10^{-3}}

               d = 1.047 x 10⁻³ m

               d = 1.047 mm

diameter of the wire is d = 1.047 mm

5 0
3 years ago
50 POINTS AND BRAINLIST!!!PLEASE HELP FOR BRAINLIST! Give answer and explanation/ work
UkoKoshka [18]

20 joule is your answer

Answer:

here

mass m =100kg

distance d=50m

acceleration due to gravity a =10m/s²

work =force×displacement

= ma/d=100×10/50=20joule

4 0
3 years ago
Read 2 more answers
Gravity is a force of action that acts _______.
8090 [49]
I believe the answer is D.
8 0
4 years ago
Read 2 more answers
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