Answer:
We need 0.375 mol of CH3OH to prepare the solution
Explanation:
For the problem they give us the following data:
Solution concentration 0,75 M
Mass of Solvent is 0,5Kg
knowing that the density of water is 1g / mL, we find the volume of water:
Now, find moles of 
are needed using the molarity equation:
therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH, resulting in a concentration of 0,75M
Answer:
Energy was released when the sodium and hydroxide ions formed new bonds with the water.
Explanation:
1 mol of any particles = 6.02*10²³ particles
56 mol*6.02*10²³ molecules of water/1 mol =3.37*10²⁵
Accuracy is the closeness of a measurement to its true value. Precision is the closeness of more than one measurements to each other. The measurements of Lamant is both accurate and precise while the scale of Colin is the opposite. Kirvin is precise but he is not accurate.
Answer:
V2= 0.0796m3
Explanation:
We have that for a real gas the following relation is fulfilled:
PV / T = constant
To use this formula I need to pass the pressure of mmHg to KPa and the volume of L to m3, knowing that
1Kpa = 7.50062mmHg
1L = 0.001m3
So i can say
P1V1/T1 =P2V2/T2
So
V2= P1V1T2/P2T1
V2= 51.60KPa*0.034m3*350k/36.53KPa*211k
finally
V2= 0.0796m3
