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3 years ago

The property of metals to be made into wire is called

1 answer:

6 0

Metal have some properties like lustrous (shiny), good conductors of electricity and heat,etc. Metals have another property by which metal can be drawn into a wire by hammering on it .This property is called as 'ductility'.

hope this helps, please mark brainliest. :)

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What is the molar mass of a gas with a density of 3.50 g/L at a

Kruka [31]

Answer:

<u>104 g/mol</u>

Explanation:

Use the ideal gas equation:

$pV=nRT$

Where:

p is pressure: 0.950atm
V is volume: unknown
n is number of moles: unknown
R is the universal constat of gases: 0.08206 atm.liter/ (K.mol)
T is the absolute temperature: 345K

Use the <em>molar mass</em> of the gas to include the density in the formula:

molar mass = mass in grams / number of moles

⇒ mass in grams = number of moles × molar mass

density = mass in grams / volume

⇒ density = number of moles × molar mass / volume

density = (n/V) × molar mass

⇒ n/V = density / molar mass

Clear n/V from the gas ideal equation and subsittute with density/molar mass:

n/V = p/(RT)

density / molar mass = n/V

density/molar mass = p/(RT)

molar mass = density × RT / p

Now you can subsitute the data:

molar mass = (3.50g/liter) × 0.08206 atm.liter/(K.mol) × 345K / 0.950 atm

molar mass = 104.3 g/mol

Round to the nearest whole number: 104g/mol ← answer

3 0

3 years ago

What is the pOH of a 1 x 10^-8 M solution of HNO3?

Sedaia [141]

Explanation:

to find POH u need PH first

so ph=-log(h3o)

$ph = - log(1 \times {10}^{ - 8} ) \\ \\ ph = 8 \\ ph + poh =14 \\ poh = 14 - 8 \\ poh = 6$

8 0

3 years ago

3. How many moles of aluminum are needed to react completely with 1.2 mol of FeO?

hoa [83]

Answer:

ssf

Explanation:

3 0

3 years ago

The gas in a container is at a pressure of 3.00 atm at 25.0 C. Directions on the container warn the user no to keep it in a plac

Nimfa-mama [501]

Answer:

$P_{2} = 3.272\,atm$

Explanation:

Let consider that gas behaves ideally, the following relation is used:

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

The final pressure is:

$P_{2} = P_{1} \cdot \frac{T_{2}}{T_{1}}$

$P_{2} = (3\,atm)\cdot \left(\frac{325.15\,K}{298.15\,K} \right)$

$P_{2} = 3.272\,atm$

4 0

3 years ago

(3.6 x 104) / (4 x 10-6)

Feliz [49]

Answer:

930 pls mark me branilest

4 0

3 years ago

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