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mojhsa [17]
3 years ago
11

When there are 165.0grams of reactants, what is the mass of the products for that reaction?

Chemistry
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

165.0 grams

Explanation:

The law of conservation of mass tells us that the mass of the reactants will be equal to the mass of the products. Therefore, if we begin with 165.0 grams of mass, that is how much there will be at the end in the products, even if it's in different forms.

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How to we know how many neutrons are in the atoms we draw models for ? (We represent average atoms, not ions or isotopes)
Delvig [45]

Answer:

Atoms is the smallest unit of a chemical element and consist of three main components protons, neutrons, and electrons.

The number of a neutron is based on the difference between the mass number of the atom (M) and the atomic number (Z). every isotope of an element has a different number of neutron.

But in a neutral atom or average atom, the number of neutrons is equal to the number of protons and the number of electron.

Example of the number of neutrons in an average atom: In Nitrogen-14, the atomic number and the number of protons is 7, it means the number of neutrons will also 7.

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3 years ago
Examples of pure and impure substances
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Pure- table salt
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8 0
3 years ago
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For the following equation: 4NH3(g) + 7O2(g) ® 4NO2(g) + 6H2O(g), how many moles of ammonia (NH3) will be required to produce 10
Mariulka [41]

Answer:

6.67 moles of NH₃

Explanation:

From the equation of reaction,

4NH₃(g) + 7O₂(g) → 4NO₂(g) + 6H₂O(g),

4 moles of NH₃ will produce 6 moles of 6H₂O,

X moles of NH₃ will produce 10 moles of H₂O

X = (10 * 4) / 6

X = 6.67 moles of NH₃

6.67 moles of NH₃ will produce 10 moles of H₂O

7 0
4 years ago
Initially, a 55.0 liter compressible container, holding 2.4 moles of a gas, exerts a pressure of 760 millimeters of mercury at a
Bingel [31]
You would have to use the ideal gas law for this:
PV=nRT
Pressure, Volume, n=moles, R gas constant, Temperature in Kelvin
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5 0
3 years ago
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What would be the mass of 9.03*10^21 molecules of hydrobromic acid
Fynjy0 [20]

Answer:

2.11 g hydrobromic acid (correct to 3SF)

Explanation:

Molecular formula of hydrobromic acid = C2H5BrO2

mass of C2H5BrO2 = 140.96g

Beginning with what we're given, 9.03*10^21 we then make a conversion by using Avegadro's number which is 6.02*10^23 per mole (Oct. 23 at 6:02 am is national mole day :) Then, we need to convert out of moles, 140.96g hydrombromic acid per mole.

It looks like this:

9.03*10^21 molecules • (1 mol C2H5BrO2 / 6.02*10^23 molecules) • (140g C2H5BrO2 / 1 mol) = 2.1144 g C2H5BrO2

3 0
3 years ago
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