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3 years ago

In the product 6o2 what does the coefficient mean

Physics

2 answers:

Slav-nsk [51]3 years ago

8 0

Answer:

The number multiplied by the variable

Explanation:

Lostsunrise [7]3 years ago

3 0

Answer:

a numerical or constant quantity placed before and multiplying the variable in an algebraic expression example ( 4 in 4x y).

Explanation:

Hope this helps! Brainly if so!

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The endocrine system consists of: (2 points)

motikmotik

Answer: Glands

Explanation: Glands are the structures of the endocrine system that produce and secrete hormones.

8 0

3 years ago

A 1 kg ball and a 10 kg ball are dropped from a height of 10 m at the same time. In the absence of air resistance,

koban [17]

Answer: A

Explanation: Neglecting air resistance every object will return to the ground at the same interval regardless of their weights, we can say that the objects are undergoing free falls, they are falling under the sole of gravity.

No matter the weight of the objects or the elevation, without significant air resistance, they will reach the ground at the same time.

7 0

4 years ago

The Moon requires about 1 month (0.08 year) to orbit Earth. Its distance from us is about 400,000 km (0.0027 AU). Use Kepler’s t

dem82 [27]

Answer:

$\frac{M_e}{M_s} = 3.07 \times 10^{-6}$

Explanation:

As per Kepler's III law we know that time period of revolution of satellite or planet is given by the formula

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

now for the time period of moon around the earth we can say

$T_1 = 2\pi\sqrt{\frac{r_1^3}{GM_e}}$

here we know that

$T_1 = 0.08 year$

$r_1 = 0.0027 AU$

$M_e$ = mass of earth

Now if the same formula is used for revolution of Earth around the sun

$T_2 = 2\pi\sqrt{\frac{r_2^3}{GM_s}}$

here we know that

$r_2 = 1 AU$

$T_2 = 1 year$

$M_s$ = mass of Sun

now we have

$\frac{T_2}{T_1} = \sqrt{\frac{r_2^3 M_e}{r_1^3 M_s}}$

$\frac{1}{0.08} = \sqrt{\frac{1 M_e}{(0.0027)^3M_s}}$

$12.5 = \sqrt{(5.08 \times 10^7)\frac{M_e}{M_s}}$

$\frac{M_e}{M_s} = 3.07 \times 10^{-6}$

4 0

3 years ago

Which activities demonstrate speed the most? <br> Look at pic

steposvetlana [31]

B: Sprinting. It is the best answer because it demonstrates speed better than the others

5 0

3 years ago

a ball rolls off a platform that is 12 m above ground. The ball's horizontal velocity as it leaves the platform is 5 m/s. How mu

jonny [76]

The time it takes for the ball to hit the ground from the platform is determined as 1.56 seconds.

<h3>Time of motion of the ball</h3>

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

where;

v is initial vertical velocity = 0
t is time of motion
h is height of fall of the ball

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 12 / 9.8)

t = 1.56 seconds

Thus, the time it takes for the ball to hit the ground from the platform is determined as 1.56 seconds.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

5 0

2 years ago