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Kay [80]
3 years ago
15

Minerals that form from magma process will tend to form ?

Physics
1 answer:
NISA [10]3 years ago
3 0

igneous rocks, and can either be entrusive or extrusive.

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The period of physical changes to sex characteristics that marks the beginning of adolescence in males and females is
tatyana61 [14]

The period of physical changes to sex characteristics that marks the beginning of adolescence in males and females is Puberty.

6 0
3 years ago
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A runner completes the 200-meter dash with a time of 19.80 seconds. What was the runner's average speed in miles per hour?
andriy [413]

Answer:

v = 22.54 mph.

Explanation:

Given that,

Distance moved, d = 200 m

Time, t = 19.8 s

We need to find the runner's average speed.

We know that,

1 mile = 1609.34 m

200 m = 0.124 miles

19.8 seconds = 0.0055 h

So,

Speed = distance/time

v=\dfrac{0.124}{0.0055}\\\\v=22.54\ mph

So, the runner's average speed is 22.54 mph.

4 0
3 years ago
3. Infiltration is the process by which rainwater becomes
amid [387]
<em></em>Your answer is :<em>

A.
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Groundwater.<em>

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4 0
4 years ago
The tilt of the Earth's axis of rotation changes from approximately 22.5° to 24.5° over a period of 41,000 years. This causes gl
kompoz [17]
<span>b. less climatic variation between the summer and winter seasons in the middle and high latitudes

As the tilt becomes higher (approaches 24 degrees) there is greater variation between the summer and winter months, due to the fact that the tilt toward the sun in the summer and away from the sun in the winter are more pronounced. </span>
3 0
3 years ago
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chapter 2 linear motion problems a student launches an arrow upward with an unknown initial velocity. the arrow takes 2.3 second
anzhelika [568]

Answer:

V_{0}= 22.5\frac{m}{s} and Ymax=25.8m

Explanation:

Velocity at any time is given by V=V_{0}sin\theta -gt. but when the arrow is on the top its velocity is zero and if it is launched upward the angle is 90°, so.

0=V_{0} sin90-gt

V_{0}=gt=9.8\frac{m}{s^{2}}.2.3s=22.5\frac{m}{s}

At the maximun height, position is given by Ymax=V_{0}sin\theta.t-\frac{1}{2}gt^{2}, replacing Ymax=22.5\frac{m}{s}x2.3s-\frac{1}{2}x9.8x(2.3)^{2}=25.8\frac{m}{s}

5 0
3 years ago
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