21 With a negative pressure respirator, when you inhale, you pull air through a filter and when you exhale, a valve

Explain about Absolute viscosity, kinematic viscosity and SUS?

ArbitrLikvidat [17]

Answer:

Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid flow

Kinematic viscosity relates to the dynamic viscosity and density proportion.

SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity

Explanation:

Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid flow, whereas Kinematic viscosity relates to the dynamic viscosity and density proportion. fluid with distinct kinematic viscosities may have similar dynamic viscosities and vice versa.Dynamic viscosity provides you details of power required to make the fluid flow at some rate, however kinematic viscosity shows how quick the fluid moves when applying a certain force.

SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity when change with change in temperature. it is measured by using viscosimeter.

3 0

3 years ago

Proper ventilation is required when welding, so that you don't ____________.

galben [10]

I say the answers is A but if you mean ventilation in the area of the room then answer B

4 0

3 years ago

Read 2 more answers

An o ring intended for use in a hydraulic system using MIL-H-5606 (mineral base) fluid will be marked with

Alex_Xolod [135]

An o ring intended for use in a hydraulic system using MIL-H-5606 (mineral base) fluid will be marked with a blue stripe or dot.

8 0

2 years ago

The inner surface of a hollow cylinder is subjected to tangential and axial stresses of 40,000 and 24,000 psi, respectively. Det

Furkat [3]

Answer:

15,000 psi

Explanation:

The solution / solving is attach below.

5 0

3 years ago

The human eye, as well as the light-sensitive chemicals on color photographic film, respond differently to light sources with di

jeka57 [31]

Answer:

a) at T = 5800 k

band emission = 0.2261

at T = 2900 k

band emission = 0.0442

b) daylight (d) = 0.50 μm

Incandescent ( i ) = 1 μm

Explanation:

To Calculate the band emission fractions we will apply the Wien's displacement Law

The ban emission fraction in spectral range λ1 to λ2 at a blackbody temperature T can be expressed as

F ( λ1 - λ2, T ) = F( 0 ----> λ2,T) - F( 0 ----> λ1,T )

Values are gotten from the table named: blackbody radiation functions

a) Calculate the band emission fractions for the visible region

at T = 5800 k

band emission = 0.2261

at T = 2900 k

band emission = 0.0442

attached below is a detailed solution to the problem

b)calculate wavelength corresponding to the maximum spectral intensity

For daylight ( d ) = 2898 μm *k / 5800 k = 0.50 μm

For Incandescent ( i ) = 2898 μm *k / 2900 k = 1 μm

3 0

3 years ago