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3 years ago

Is there anyone who can help me with welding?

Engineering

1 answer:

Artist 52 [7]3 years ago

8 0

Answer:

I do know some things on welding. Though I don't know what kind of welding you mean ill give you some simple tips.

Explanation:

When welding make sure there are no air pockets or the whole piece of material will break. Always watch your piece closely, letting your eyes off for a minute could be the end. Always weld your piece onto the handle as strongly as possible. If you don't have I good handle it will fall off. Also always wear goggles so nothing gets in your eye. Hope this helps!

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Can some please help me with my questions. The Questions are in these two pictures below. I don't know how to do this question.

ololo11 [35]

Answer: ok if you need help go to help me with a question.com

Explanation:

5 0

3 years ago

Car B is traveling a distance dd ahead of car A. Both cars are traveling at 60 ft/s when the driver of B suddenly applies the br

vagabundo [1.1K]

Answer:

Explanation:

Using the kinematics equation $v = v_o + a_ct$ to determine the velocity of car B.

where;

$v_o =$ initial velocity

$a_c$ = constant deceleration

Assuming the constant deceleration is = -12 ft/s^2

Also, the kinematic equation that relates to the distance with the time is:

$S = d + v_ot + \dfrac{1}{2}at^2$

Then:

$v_B = 60-12t$

The distance traveled by car B in the given time (t) is expressed as:

$S_B = d + 60 t - \dfrac{1}{2}(12t^2)$

For car A, the needed time (t) to come to rest is:

$v_A = 60 - 18(t-0.75)$

Also, the distance traveled by car A in the given time (t) is expressed as:

$S_A = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2$

Relating both velocities:

$v_B = v_A$

$60-12t = 60 - 18(t-0.75)$

$60-12t =73.5 - 18t$

$60- 73.5 = - 18t+ 12t$

$-13.5 =-6t$

t = 2.25 s

At t = 2.25s, the required minimum distance can be estimated by equating both distances traveled by both cars

i.e.

$S_B = S_A$

$d + 60 t - \dfrac{1}{2}(12t^2) = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2$

$d + 60 (2.25) - \dfrac{1}{2}(12*(2.25)^2) = 60 * 0.75 +60((2.25)-0.75) -\dfrac{1}{2}*18*((2.25)-0.750)^2$

d + 104.625 = 114.75

d = 114.75 - 104.625

d = 10.125 ft

3 0

3 years ago

In order to test the reverse route back towards the original host, which of the following will you use? A Standard ping B Extend

Vlad1618 [11]

The function that you will use in order to test the reverse route back toward the original host is known as Extended ping. Thus, the correct option for this question is B.

<h3>What is Ping and traceroute for?</h3>

Ping and traceroute are the common commands you can effectively utilize in order to troubleshoot network problems. Ping is a simple command that can typically test the reachability of a device on the network. While traceroute is a command you use to 'trace' the route that a packet takes when traveling to its destination.

Extended ping permits a router's ping command to use The router's LAN IP address from within the subnet, fully testing the route back to the subnet. A standard ping often does not test the reverse route that you need to back toward the original host.

Therefore, the function that you will use in order to test the reverse route back toward the original host is known as Extended ping. Thus, the correct option for this question is B.

To learn more about Ping and traceroute, refer to the link:

brainly.com/question/28333920

#SPJ1

6 0

1 year ago

A westbound section of freeway currently has three 12-ft wide lanes, a 6-ft right shoulder, and no ramps within 3 miles upstream

alisha [4.7K]

Answer:

The level of the service is loss and the density is 34.2248 pc/mi/ln

Explanation:

the solution is attached in the Word file

Download docx