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Anna71 [15]
3 years ago
13

What is five plus forty five

Chemistry
2 answers:
zhenek [66]3 years ago
8 0

Answer:

55. I hope this helps you!

ziro4ka [17]3 years ago
5 0

Answer:

5+ 45 = 50 is the answer....

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when you started the activity, the can was open to the air outside tge can. how did the air pressure inside the can compare to t
aliya0001 [1]

The air pressure inside the can is lower compared to that of outside air pressure.

Explanation:

  • In general, the air pressure of an already opened can will be the same as the outside pressure.
  • Since the can is evacuated and remain as vacuum, so there will be no pressure difference in it.
  • If the can opens, air inside the can push the top and escapes to the outside.
  • This is due to high pressure experienced outside the can compare to that of lower pressure inside the can and this may even cause can to collapse itself.
7 0
3 years ago
Which of the following would label the boxes correctly?
choli [55]
The last one 1) exothermic; 2) exothermic
5 0
3 years ago
For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
3 years ago
Calculate the volume of a 2.0 molar aqueous solution made from 14 miles of K2S
Vilka [71]

Answer:

volume is 7.0 liters

Explanation:

We are given;

  • Molarity of the aqueous solution as 2.0 M
  • Moles of the solute, K₂S as 14 moles

We are required to determine the volume of the solution;

We need to know that;

Molarity = Moles ÷ volume

Therefore;

Volume = Moles ÷ Molarity

Thus;

Volume of the solution = 14 moles ÷ 2.0 M

                                       = 7.0 L

Hence, the volume of the molar solution is 7.0 L

5 0
3 years ago
Change the bond between the two carbon atoms in each molecule to a double or triple bond as needed to complete the structure. If
Georgia [21]

Answer:

Your question is complex, because I think you wrote it wrong.

Although in front of this what I can help you is that the carbons are associated between a single, double or triple union.

This depends on whether they are attached to more or less carbons or hydrogens, the carbons have the possibility of joining 4 radicals, both other carbons and hydrogens.

Simple junctions talks about compound organisms called ALKANS.

The double unions, in organic these compounds are called as ALQUENOS.

And as for the tertiary unions, the organic chemistry names them as ALQUINOS.

These compounds that we write, a simple union, the less energy, the less this union, that is why the triple bond is the one that contains the most energy when breaking or destroying it in a reaction.

Explanation:

In a chemical compound the change of these unions if we modified them we would generate changes even in the classifications naming them as well as different compounds and not only that until they change their properties

6 0
3 years ago
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