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3 years ago

Calculate the number of moles of an ideal gas if it occupies 0.01 m3 under 125,000 Pa at a temperature of 357 K.

Chemistry

2 answers:

Naily [24]3 years ago

7 0

Answer : The correct option is, (A) 0.42 moles

Explanation :

Using ideal gas equation:

$PV=nRT$

where,

P = pressure of gas = 125000 Pa = 125 kPa

conversion used : (1 kPa = 1000 Pa)

V = volume of gas = $0.01m^3=10L$

conversion used : $(1m^3=1000L)$

T = temperature of gas = 357 K

n = number of moles of gaseous mixture = ?

R = gas constant = 8.314 kPa.L/mol.K

Now put all the given values in the ideal gas equation, we get:

$(125kPa)\times (10L)=n\times (8.314kPa.L/mol.K)\times (357K)$

$n=0.42mole$

Therefore, the number of moles of an ideal gas is 0.42 mole.

oksano4ka [1.4K]3 years ago

7 0

The correct answer is A. 0.42 moles.

<h3>Further Explanation</h3>

The Ideal Gas Equation states the relationship among the pressure, temperature, volume, and number of moles of a gas.

The Ideal Gas Equation is:

where:

P - pressure (in Pa)

V - volume (in m³)

n - amount of gas (in moles)

R - universal gas constant (8.314 Pa·m³/mol·K)

T - temperature (in K)

In the problem, we are given the values:

P = 125,000 Pa (3 significant figures)

V =0.01 m³ (1 significant figure)

n = ?

T = 357 K (3 significant figures)

Solving for n using the Ideal Gas Equation:

$PV = nRT$ $n = \frac{PV}{RT}\\n = \frac{125,000 \ Pa \times 0.01 \ m^3}{8.314 \frac{Pa-m^3}{mol-K} \times 357 \ K}\\n = \frac{1250 \ Pa-m^3}{2968 \frac{Pa-m^3}{mol}}\\\\\boxed {n = 0.42116 \ mol}$

The least number of significant figures is 1, therefore, the final answer must have only 1 significant figure:

$\boxed {\boxed {n = 0.4 \ mol}}$

Since this is not available, the closest answer is option A. 0.42 moles.

<h3>Learn More </h3>

1. Learn more about Boyle's Law brainly.com/question/1437490

2. Learn more about Charles' Law brainly.com/question/1421697

3. Learn more about Gay-Lussac's Law brainly.com/question/6534668

<h3>Keywords: Ideal Gas Law, Volume, Pressure</h3>

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Answer:

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Explanation:

Given data:

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3 years ago

To whoever helps me thank you so much have a wonderful day!

Schach [20]

Answer:

N and P

Explanation:

Anion:

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Cation:

When atom lose electron cation is formed. The atom thus have positive charge because number of positive charge i.e protons are increased are greater than negative charge or electron.

In given problem N and phosphorus both can gain three electrons which means negative charge becomes greater that's why the extra electron gained by atoms are written as -3 and both form anion with charge -3.

while Al form cation with charge +3 Mg form cation with charge +2 and iodine and bromine both form anion with charge of -1.

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3 years ago

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Answer:

To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).

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3 years ago

Naphthalene, commonly found in moth balls, is composed of 93.7% carbon and 6.3% hydrogen. The molar mass of naphthalene is 128 g

Vikki [24]

Answer:

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

Explanation:

Centesimal composition means that in 100 g of compound we have x g of the element. Therefore in 100 g of naphthalene we have:

93.7 g of C

6.3 g of H

Let's make a rule of three:

In 100 g of naphthalene we have 93.7 g of C and 6.3 g of H

In 128 g of naphthalene we would have:

128 . 93.7 / 100 = 120 g of C

128. 6.3 / 100 = 8 g of H

We convert the mass to moles, by molar mass:

120 g . 1mol / 12 g = 10 moles C

8 g . 1mol/ 1g = 8 moles H

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

(The sub-index of each element is divided by the largest possible number)

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4 years ago

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