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3 years ago

Select the correct answer.

Chemistry

2 answers:

alexdok [17]3 years ago

8 0

The answer is power. Power is the only answer here that relates to force.

solniwko [45]3 years ago

3 0

Answer:

Power

Explanation:

#platofam

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Car wax mostly contains beeswax and carnauba wax. These large hydrocarbons are ideal to use because they _____ water.

hichkok12 [17]

These waxes are highly hydrophobic (repellant) of water, so the correct answer would be D) repel.

The wax coating put on the car creates a water repellant sheila that causes the water to bead up on the surface of the wax, rather than directly impacting the paint and surface of the body of the car. This prolongs the life and quality of the appearance of the car.

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3 years ago

Read 2 more answers

Give me lil reasoning so I know your not lying for points

Delvig [45]

Answer:

As the temperature increases the pressure increases.

Explanation:

This graph has a positive slope, meaning that there is a direct relationship between the two graphed variables.

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3 years ago

onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency

mestny [16]

Answer : The excess reactant is, $H_2O$

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of $CaCN_2$ = 105.0 g

Mass of $H_2O$ = 78.0 g

Molar mass of $CaCN_2$ = 80.11 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $CaCO_3$ = 100.09 g/mole

First we have to calculate the moles of $CaCN_2$ and $H_2O$ .

$\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles$

$\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $CaCN_2$ react with 3 mole of $H_2O$

So, 1.31 moles of $CaCN_2$ react with $1.31\times 3=3.93$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $CaCN_2$ is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

$\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)$

$\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g$

Thus, the leftover amount of excess reagent is, 7.2 grams.

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3 years ago

Which of the following is a homogenous mixture of two or more pure substances?

pashok25 [27]

The and is a alcohol

6 0

3 years ago

What element has an r.m.m of 72

igomit [66]

Answer:

Germanium

Explanation:

The element Germanium is one with a relative molecular mass of 72. This corresponds to the mass number of this element.

Relative molecular mass of an element is the mass of a formula unit to that of a carbon-12 atom.

The chemical symbol of Germanium is Ge. It is a lustrous and hard metalloid belonging to the carbon group.

It was discovered by Clemens Alexander Winkler.

7 0

3 years ago