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grin007 [14]
4 years ago
5

Two loudspeakers 42.0 m apart and facing each other emit identical 115 Hz sinusoidal sound waves in a room where the sound speed

is 345 m/s. Susan is walking along a line between the speakers. As she walks, she finds herself moving through loud and quiet spots. If Susan stands 19.5 m from one speaker, is she standing at a quiet spot or a loud spot?
Physics
1 answer:
Korvikt [17]4 years ago
5 0

Answer:

She will be standing at a loud spot.

Explanation:

In order to define if Susan is standing at a quiet spot or a loud spot, we need to know first the difference in the path of the sound that reach to Susan from one speaker and the one from the other speaker.

If we call d₁ to the distance from speaker A, that we know is equal to 19.5m, the distance d₂ to the other speaker will be as follows:

d₂ = 42.0 m - 19.5m = 22.5 m

So, the difference in path for both speakers is just:

d = d₂-d₁ = 22.5 m -19.5 m = 3.0 m

Now, we need to relate this distance with the wavelength of the sound, as we know for a constructive interference, the difference in the paths must be equal to an even multiple of the semi-wavelength, as follows:

d = (2n)*(λ/2)

In order to get the value of λ, we know that at any wave, there exists a fixed relationship between the speed, the frequency and the wavelength:

v = λ*f

If v = 345 m/s and f= 115 1/sec, we can easily solve for λ:

λ = v/f = 345 m/s / 115 (1/s) = 3.0 m

As the difference between the distances from both speakers to Susan equals exactly to one wavelength, this means that both arrive in the same phase, which means that there will be a constructive interference, i.e., it will be a loud spot.

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Answer:

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In this case, both the shrimp and the predator do not live on each other, since they feed independently.

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The correct answer is: the balloon benefits by getting a burrow to live in and the shrimp knows when predators are nearby.

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The small intestine _____.
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A cart of mass 6.0 kg moves with a speed of 3.0 m/s towards a second stationary cart with a mass of 3.0 kg. The carts move on a
IgorLugansk [536]

Answer:1.5

Explanation:

Given

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initial Velocity u_1=3 m/s

mass of second cart m_2=3 kg

u_2=0 m/s

In the absence of External Force we can conserve momentum

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{m_1+m_2}

v=\frac{6\times 3+3\times 0}{6+3}

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K.E._2=\frac{1}{2}\cdot (3+6)\cdot (2)^2

K.E._2=18 J

Initial Kinetic Energy

K.E._1=\frac{1}{2}m_1u_1^2+\frac{1}{2}m_2u_2^2

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ratio =\frac{K.E._1}{K.E._2}=\frac{27}{18}=1.5

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4 years ago
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Answer:

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We can use the Energy conversion law

Energy can not be made or destroyed. It can only be converted to another form of energy

Potential Energy (PE) is the energy an object has due to its height of the location

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Simply here , lemming had a PE and KE also.  

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Answer:

ANswers

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