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Zepler [3.9K]
3 years ago
11

Fred points a toy laser gun at a wall. Considering that the frequency of the gun's light is 4.91 × 1014 hertz and that Planck’s

constant is 6.61 × 10-34 joule·seconds, what is the energy of the laser light?
A) 3.24 × 10-21 joules
B) 4.91 × 1015 joules
C) 2.04 × 10-21 joules
D) 4.92 × 10-18 joules
Physics
2 answers:
vladimir1956 [14]3 years ago
6 0
E=hf 

<span>E=6.61x10^34x4.91x10^14 </span>
<span>E=3.24x10^21 joules </span>

<span>Answer is A </span>
Stella [2.4K]3 years ago
4 0
The answer is 3.24 x 10^-21
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Answer with Explanation:

We are given that

Diameter of coil=d=0.115mm

Radius, r=\frac{d}{2}=\frac{0.115}{2}=0.0575mm=0.0575\times 10^{-3} m

Using 1mm=10^{-3} m

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T_0=20^{\circ} C

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(a).We know that

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\rho=2.82\times 10^{-8}(1+3.9\times 10^{-3}(55-20))

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Using the formula

J=\frac{0.235}{3.2\times 10^{-8}}=7.3\times 10^6A/m^2

c.Total current,I=JA

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Using the formula

I=7.3\times 10^6\times 3.14\times (0.0575\times 10^{-3})^2

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