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djverab [1.8K]
2 years ago
11

What is the total wavelength if one-half of the wave is 3?

Physics
1 answer:
seraphim [82]2 years ago
3 0

Answer:

6

Explanation:

Half the wave = 3

Wavelength = 3 x 2 = 6

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Cruising at 35,000 feet in an airliner, straight toward the east,

at 500 miles per hour

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7. Which of the following is NOT always true about a synthesis reaction!
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What is the relationship between the speed of an object and its kinetic energy?
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For the purposes of your question, we can think of speed and velocity as being the same thing. Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the kinetic energy will increase by a factor of four.

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Review. One electron collides elastically with a second electron initially at rest. After the collision, the radii of their traj
DochEvi [55]

The energy of the incident electron in keV is 5.51× 10—²² keV.

Capacity or ability to do work is termed energy. Energy exists in various forms. It can be in the form of mechanical, potential, thermal, kinetic, and many other forms. Joules is the SI of the energy. The potential energy of a system is defined as the energy stored due to its position. While kinetic energy is defined as the energy

stored due to its position.

Radius1 of the trajectory = 1.00 cm

Radius2 of the trajectory = 2.4 0 cm

The magnitude of the uniform magnetic field = 0.0440 T

A Uniform magnetic field is perpendicular to the trajectories.

The velocity of the incident electron is,

v =  \frac{eBR}{m}

The energy of the incident electron is,

K =  \frac{1}{2} mv ^{2}

K =  \frac{1}{2} \frac{(eBR)}{m}^{2}

The energy in keV is,

1-kilo electron volt = 1000 electron volts

1 keV = 1000 eV

1 \: eV =  \frac{1}{1000} \:  keV

= \frac{ K}{1000}

=  \frac{eB ^{2} R ^{2} }{2000m}

= 5.51 \times 10 ^{ - 22}  \: keV

Therefore, the energy of the incident electron in keV is 5.51× 10—²² keV.

To know more about electrons, refer to the below link:

brainly.com/question/1255220

#SPJ4

6 0
1 year ago
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