The percent composition of this compound :
Mg = 72.182%
N = 27.818%
<h3>Further explanation</h3>
Given
9.03 g Mg
3.48 g N
Required
The percent composition
Solution
Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements
Total mass of the compound :
= 9.03 g + 3.48 g
= 12.51 g
The percent composition :
Mg : 9.03/ 12.51 g x 100% = 72.182%
N : 3.48 / 12.51 g x 100% = 27.818%
Answer:
Ruler
Explanation:
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Answer:
30moles of SiO₂
Explanation:
Given parameters:
Number of moles of O₂ = 30moles
Unknown:
Number of moles of SiO₂ = ?
Solution:
To solve this problem, we need to write the reaction expression:
Si + O₂ → SiO₂
The reaction is balanced;
1 mole of O₂ will produce 1 mole of SiO₂
30mole of O₂ will produce 30moles of SiO₂
The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.
So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl.