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V125BC [204]
3 years ago
6

A sample of krypton occupies 15.0 L at a pressure of 2.1 atm. Use Boyle's Law to find the pressure of the krypton when the volum

e is decreased to 4L.
Chemistry
1 answer:
denis23 [38]3 years ago
4 0

Answer:

7.5 atm

Explanation:

Given that,

Initial volume, V₁ =  15 L

Pressure, P₁ = 2.1 atm

Final volume, V₂ = 4L

We need to find the final pressure. The mathematical relation between volume and pressure is given by :

\dfrac{V_1}{V_2}=\dfrac{P_2}{P_1}\\\\P_2=\dfrac{V_1P_1}{V_2}\\\\P_2=\dfrac{15\times 2}{4}\\\\P_2=7.5\ atm

So, the final pressure is equal to 7.5 atm.

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Answer:

\begin{array}{cccll}\textbf{Element 1} & \textbf{ Element 2} &\textbf{Compound?} &\textbf{Formula} &\textbf{Type}\\\text{Ar}&\text{Xe} &\text{No} &\text{None}&\text{Neither}\\\text{F}& \text{Cs} &\text{Yes} &\text{CsF} &\text{Ionic}\\\text{N} &\text{Br} &\text{Yes} & \text{NBr}_{3}&\text{molecular} \\\end{array}

Explanation:

You look at the type of atom and their electronegativity difference.

If ΔEN <1.6, covalent; if ΔEN >1.6, ionic

Ar/Xe: Noble gases; no reaction

F/Cs: Non-metal + metal; ΔEN = |3.98 – 0.79| = 3.19; Ionic

N/Br: Two nonmetals; ΔEN = |3.04 - 2.98| = 0.

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Explanation:

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