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2 years ago

4. Calculate the empirical formula for the following compounds Na=32.4% S=22.6 % O=45.0%

Chemistry

1 answer:

lilavasa [31]2 years ago

7 0

Answer:

Na2 S O4

Explanation:

Na mole wt 22.989

32.4 / 22.989 = 1.4093

S mole wt = 32.06

22.6/32.06 = .7049

O mole wt = 15.999

45 / 15.999 = 2.8127 Now divide all of the results by the smallest

Na 1.4093 / .7049 = 2

S .7049/.7049 = 1

O 2.8127 /.7049 = 4 so Na2 S O4

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Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 9.045×10−2 −mg sample of menthol i

Ket [755]

Answer:

Empirical Formula = C₁₀H₂₀O

Solution:

Data Given:

Mass of Menthol = 9.045 × 10⁻² mg = 9.045 × 10⁻⁵ g

Mass of CO₂ = 0.2546 mg = 0.0002546 g

Mass of H₂O = 0.1043 mg = 0.0001043 g

Step 1: Calculate %age of Elements as;

%C = (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

%C = (0.0002546 ÷ 9.045 × 10⁻⁵) × (12 ÷ 44) × 100

%C = (2.814) × (12 ÷ 44) × 100

%C = 2.814 × 0.2727 × 100

%C = 76.73 %

%H = (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

%H = (0.0001043 ÷ 9.045 × 10⁻⁵) × (2.02 ÷ 18.02) × 100

%H = (1.153) × (2.02 ÷ 18.02) × 100

%H = 1.153 × 0.1120 × 100

%H = 12.91 %

%O = 100% - (%C + %H)

%O = 100% - (76.73% + 12.91%)

%O = 100% - 89.64%

%O = 10.36 %

Step 2: Calculate Moles of each Element;

Moles of C = %C ÷ At.Mass of C

Moles of C = 76.73 ÷ 12.01

Moles of C = 6.3888 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 12.91 ÷ 1.01

Moles of H = 12.7821 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 10.36 ÷ 16.0

Moles of O = 0.6475 mol

Step 3: Find out mole ratio and simplify it;

C H O

6.3888 12.7821 0.6475

6.3888/0.6475 12.7821/0.6475 0.6475/0.6475

9.86 19.74 1

≈ 10 ≈ 20 1

Result:

Empirical Formula = C₁₀H₂₀O₁

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3 years ago

What do you know about Relative Dating

gizmo_the_mogwai [7]

it tells you the sequence in which events occurred, not how long ago they occurred.

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3 years ago

CO2 element number x Atomic mass =total mass

MaRussiya [10]

Answer:

Number= 6

Atomic mass= 12,01115

Explanation:

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3 years ago

If the copper cube had a mass of 28.7 grams and a volume of 3.2 mL, what would its density be?

Otrada [13]

Answer:

ρ=m÷v

=28.7÷3.2

≈8.97 g/m³

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3 years ago

Consider the following types of electromagnetic radiation:

liq [111]

Explanation:

Electromagnetic wave Wavelength

(1) Microwave = 1 m to 1 mm = $10^9 nm$ to $10^6 nm$

(2) Ultraviolet = 10 nm to 400 nm

(3) Radio waves = 1 mm to 100 km = $10^6 nm$ to $10^{14}nm$

(4) Infrared = 700 nm to 1 mm

(5) X-ray = 0.01 nm to 10 nm

(6) Visible = 400 nm t0 700 nm

a) In order of increasing wavelength:

: 5 < 2 < 6 < 4 < 1 < 3

b) Frequency of the electromagnetic wave given as:

$\nu=\frac{c}{\lambda }$

$\nu$ = frequency

$\lambda$ = Wavelength

c = speed of light

$\nu \propto \frac{1}{\lambda }$

So, the increasing order of frequency:

: 3 < 1 < 4 < 6 < 2 < 5

c) Energy(E) of the electromagnetic wave is given by Planck's equation :

$E=h\nu$

$E\propto \nu$

So, the increasing order of energy:

: 3 < 1 < 4 < 6 < 2 < 5

6 0

3 years ago