a truck can travle 300 miles in the same time that it takes a car to travel 330 miles. If the truck's rate is 5 miles per hour s
1 answer:
<h2>The speed of car is 55 miles per hour and speed of truck is 50 miles per hour .</h2>
Explanation:
Let the speed of the car is v miles/h , therefore the speed of truck is ( v - 5 ) miles per hour .
Because time =
Thus in case of truck the time t₁ =
In case of car the time t₂ =
But time is the same in both cases , therefore
=
or 30 v = 1650
or v = 55 miles per hour
Therefore speed of car is 55 miles per hour
Thus speed of truck is 50 miles per hour
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Answer:
468 m
Explanation:
So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.
The length CE is length AE - length AC = 284 - 234 = 50 m
We can calculate the angle ECD:
This is also the angle ACB, so we can find the length AB:
So the height of the building is 468m
F=nmv
where;
n=no. of bullets = 1
m=mass of bullets=2g *10^-3
V=velocity of bullets200m/sec
F=1
loss in Kinetic energy=gain in heat energy
1/2MV^2=MS∆t
let M council M
=1/2V^2=S∆t
M=2g
K.E=MV^2/2
=(2*10^-3)(200)^2/2
2 councils 2
2*10^-3*4*10/2
K.E=40Js
H=mv∆t
(40/4.2)
40Js=40/4.2=mc∆t
40/4.2=2*0.03*∆t
=158.73°C
