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IgorLugansk [536]
3 years ago
5

a truck can travle 300 miles in the same time that it takes a car to travel 330 miles. If the truck's rate is 5 miles per hour s

lower than the car's find the average rate for each
Physics
1 answer:
yanalaym [24]3 years ago
5 0
<h2>The speed of car is 55 miles per hour  and speed of truck is 50 miles per hour .</h2>

Explanation:

Let the speed of the car is v miles/h , therefore the speed of truck is ( v - 5 ) miles per hour .

Because time = \frac{Distance}{Speed}

Thus in case of truck the time t₁ = \frac{300}{v-5}

In case of car the time t₂ = \frac{330}{v}

But time is the same in both cases , therefore

\frac{300}{v-5} = \frac{330}{v}

or  30 v = 1650  

or v = 55 miles per hour

Therefore speed of car is 55 miles per hour

Thus speed of truck is 50 miles per hour

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One uniform ladder of mass 30 kg and 10 m long rests against a frictionless vertical wall and makes an angle of 60o with the flo
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Answer:

   μ = 0.37

Explanation:

For this exercise we must use the translational and rotational equilibrium equations.

We set our reference system at the highest point of the ladder where it touches the vertical wall. We assume that counterclockwise rotation is positive

let's write the rotational equilibrium

           W₁  x/2 + W₂ x₂ - fr y = 0

where W₁ is the weight of the mass ladder m₁ = 30kg, W₂ is the weight of the man 700 N, let's use trigonometry to find the distances

             cos 60 = x / L

where L is the length of the ladder

              x = L cos 60

            sin 60 = y / L

           y = L sin60

the horizontal distance of man is

            cos 60 = x2 / 7.0

            x2 = 7 cos 60

we substitute

         m₁ g L cos 60/2 + W₂ 7 cos 60 - fr L sin60 = 0

         fr = (m1 g L cos 60/2 + W2 7 cos 60) / L sin 60

let's calculate

         fr = (30 9.8 10 cos 60 2 + 700 7 cos 60) / (10 sin 60)

         fr = (735 + 2450) / 8.66

         fr = 367.78 N

the friction force has the expression

         fr = μ N

write the translational equilibrium equation

         N - W₁ -W₂ = 0

         N = m₁ g + W₂

         N = 30 9.8 + 700

         N = 994 N

we clear the friction force from the eucacion

        μ = fr / N

        μ = 367.78 / 994

        μ = 0.37

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The angular speed of the device is 1.03 rad/s.

<h3>What is the conservation of angular momentum?</h3>

A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.

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