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3 years ago

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Indicate all ways in which the graph used in question 4 would change if the Normal Force applied to the object was increased. Be

specific. (What happens to slopes? Y-values? X-values? Etc.)

1 answer:

Maksim231197 [3]3 years ago

5 0

Answer:

Answer:

PLEASE BRAINLESS ME INEED

# CARRY ON LEARNINGAnswer:

PLEASE BRAINLESS ME INEED

# CARRY ON LEARNING

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Using two billiard balls, in 3-4 sentences, design an experiment to demonstrate the law of conservation of momentum.

kolezko [41]

Answer:

In the explanation

Explanation:

<u>Experiment</u>:

Consider two billiard balls of masses ‘m₁’ and ‘m₂’, moving with velocities ‘u₁’ and ‘u₂’, respectively, such that u₁ is greater than u₂. After some time, these balls collide with each other and their velocities become ‘v₁’ and ‘v₂’, respectively.

<u>Observation</u>:

The masses of balls should be measured and their initial and final velocities should be measured.

<u>Result</u>:

In order to prove law of conservation of moment following equation must be satisfied by observed values:

$Total\ Momentum\ Before\ Collision = Total\ Momentum\ After\ Collision\\\\m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}$

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3 years ago

"Which of the following statements are true?

Neko [114]

Answer: im sure its <u>A only </u>

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3 years ago

Define what an astronomical unit is and explain why it is used.

Ivahew [28]

Answer:

AU

Explanation:

Astronomical units are used to measure the distances within solar system

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3 years ago

Read 2 more answers

A sumo wrestler is 330 pounds. How much force does the earth exert in him? Define Mass Define Weight

Oksana_A [137]

Answer:

a large matters of body with no shape is mass

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3 years ago

Two identical twins hold on to a rope, one at each end, on a smooth, frictionless ice surface. They skate in a circle about the

777dan777 [17]

Answer:

Part a)

$L = 2683.2 kg m^2/s$

Part b)

$v' = 8.60 m/s$

Part c)

$W = 4326.7 J$

Explanation:

Part a)

As we know that there is no external torque on the system of two twins

so here we will use

$L = mv r + mvr$

$L = 2(78 \times 4.30 \times 4)$

$L = 2683.2 kg m^2/s$

Part b)

Since angular momentum is conserved here as there is no external torque

so we will have

$2(m v r) = 2( m v' \frac{r}{2})$

$v' = 2v$

$v' = 8.60 m/s$

Part c)

Work done by both of them = change in kinetic energy

so we have

$W = 2(\frac{1}{2}mv'^2 - \frac{1}{2}mv^2)$

$W = m(v'^2 - v^2)$

$W = 78(8.60^2 - 4.3^2)$

$W = 4326.7 J$

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3 years ago