Answer:=14,160 kJ
Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below
Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase
C MPa m^3/kg kJ/kg kJ/kg
1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture
2 260 4.689 0.0422 2599 2797 1 Saturated Vapor
The mass initially contained in the tank is m1 = V/v1
m1 =0.85 m^3 /0.02993 m^3 /kg
= 28.4 kg
The mass finally contained in the tank is
m2 =V2/v
= 0.85 m^3 /0.0422 m^3 /kg
= 20.14 kg
The heat transfer is then
Qcv = m2u2 − m1u1 − he(m2 − m1)
Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ
Answer:
10 times
Explanation:
The weight of the person is defined as the product of mass of person and the acceleration due to gravity of that planet.
Let the gravity is g.
W = m x g .... (1)
Now the value of g depends on the mass of earth when the radius of earth is constant.
g' = 10 g
So, W' = m x g' = m x 10 g = 10 mg = 10 W (from (1)
So, the weight of the person becomes 10 times.
Locomotion is the ability to move from place to place, or the act of doing so.
