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Numbers from -998 and 999 are in between -999 and 1000.
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Answer is: the molarity of HCl found in a titration is 0.1 M.
Balanced chemical reaction between hydrochloric acid and sodium hydroxide:
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l).
From balanced chemical reaction: n(HCl) : n(NaOH) = 1 : 1.
n(HCl) = n(NaOH).
c(HCl) · V(HCl) = c(NaOH) · V(NaOH).
c(HCl) = c(NaOH) · V(NaOH) ÷ V(HCl).
c(HCl) = 0.1 M · 50 ml ÷ 50 ml.
c(HCl) = 0.1 M; molarity of hydrochloric acid.
The catabolism of glucose has an equation of C6H12O6 + 6O2 = 6CO2 +6 H20. Hence for every mole of glucose, 6 moles of CO2 is produced. Given 22 grams of CO2, that is 0.5 mol CO2, we multiply this by 1/6, we get the number of moles of glucose equal to 1/12 mol. The mass of glucose needed is obtained by multiplying this by molar mass of glucose which is 180 g/mol. This is equivalent 15 grams of glucose.
Answer:
The compound may have properties that are very different from those of the elements.
Explanation:
For example - common salt, sodium chloride ( NaCl) has very different properties from sodium and chlorine