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2 years ago

6CO2 + 6H20 → C,H120, + 602

Chemistry

1 answer:

tatyana61 [14]2 years ago

7 0

Explanation:

The equation of the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2

How many molecules of CO2 are present?

6 moles

How many atoms of oxygen are present in the reactants?

(6 * 2) + (6 * 1 ) = 12 + 6 = 18

How many atoms of carbon are present in the products?

(6 * 1 ) = 6

How many total atoms are present in C6H12O6?

6 + 12 + 6 = 24 atoms

Is the equation above balanced or unbalanced?

This is a balanced equation since the number of atoms of the elements is the same in the reactant and products.

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Why do group 7 elements have higher melting and boiling points going down?

Genrish500 [490]

Answer:

this is because the van der waals forces or also known as induced dipole-dipole interactions increase because more electrons are present within an atom as you go down

Explanation:

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3 years ago

A 35 L tank of oxygen is at 315 K with an internal pressure of 190 atmospheres. How

nata0808 [166]

Answer:

600.7 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

From the question,

Given: P = 190 atm, V = 35 L, T = 135 K

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

n = (190×35)/(135×0.082)

n = 600.7 moles of xygen

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3 years ago

You are instructed to create 900. mL of a 0.29 M phosphate buffer with a pH of 7.8. You have phosphoric acid and the sodium salt

Aleksandr [31]

Answer:

B and C

Explanation:

When we have to do a buffer solution we always have to choose the reaction that has the pKa closer to the desired pH value. When we find the pKa values we will obtain:

$pKa_1=-Log[6.9x10^-^3]=2.16$

$pKa_2=-Log[6.2x10^-^8]=7.20$

$pKa_3=-Log[4.8x10^-^13]=12.31$

The closer value is pKa2 with a value of 7.2. Therefore we have to use the second reaction. In which $H_2PO_4^-^1$ is the acid and $HPO_4^-^2$ is the base. Therefore the answer for the first question is B and the answer for the second question is C.

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2 years ago

Chamber 1 and Chamber 2 have equal volumes of 1.0L and are assumed to be rigid containers. The chambers are connected by a valve

vitfil [10]

1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)

=> p1 = 2 p2

Which is easy to demonstrate using ideal gas equation:

p1 = nRT/V = 2.0 mol * RT / 1 liter

p2 = nRT/V = 1.0 mol * RT / 1 liter

=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2

2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.

So, the pressure in both chambers (which form one same vessel) is:

p = nRT/V = 3.0 mol * RT / 2liter

which compared to the initial pressure in chamber 1, p1, is:

p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1

So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.

You can also see how the pressure in chamber 2 changes:

p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.

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3 years ago

Which of the statements listed below is negative aspect of a volcanic eruption?

mixas84 [53]

Answer:

C . the dramatic scenery created by volcanic eruptions attracts tourists.

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2 years ago