Temperature is the average amount of energy of motion of each particle of a substance<span>. That is, temperature is a measure of how hot or cold a </span>substance<span> is. In contrast, the total </span>energy of motion<span> in the </span>particles of a substance is called<span> thermal</span>energy<span>.</span>
It's one ratio per substance so say if you had N2 + 3H2 > 2NH3 (chemical equation for the synthesis of ammonia) just look at the number coefficients(for 3H2 the coefficient would be 3 and for 2NH3 the coefficient would be 2 and so on)So it would take 1mole of nitrogen to react with 3 moles of hydrogen In order to produce 2 moles of ammonia so there would be 6 ratios you could write comparing two substances at a time In a reaction involving 3 substances ^^; hope this helps somewhat ^^;
The change in pH of a 1.00 L of a buffered solution preparing by mixing 0.50 M acetic acid (Ka = 1.8 x 10^-5) and 0.50 M sodium acetate when 0.010 mole of NaOH is added is 4.75
when the same amount 0.010 mole of NaOH was added to 1.00 L of water the pH = 12
Explanation:
given that:
concentration of acetic acid = 0.50 M
Concentration of base sodium acetate = 0.50 M
ka = 1.8 x 10^-5)
pka = -log [ka]
pka = 4.74
From Henderson-Hasselbalch Equation:
pH = pKa + log ![\frac{[base]}{[acid]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D)
pH = 4.74 + Log ![\frac{[0.5]}{[0.5]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0.5%5D%7D%7B%5B0.5%5D%7D)
pH = 4.74 + 0
pH = 4.74
Number of moles of NaOH = 0.010 moles
volume 1 litre
molarity = 0.010 M
Moles of acetic acid and sodium acetate before addition of NaOH
FORMULA USED:
molarity = 
acetic acid,
0.5 = number of moles
0.5 is the number of moles of sodium acetate.
number of moles of NaOH 0.010 moles
NaOH reacts in 1:1 molar ratio with acetic acid so
number of moles in acetic acid = 0.5 - 0.010 = 0.49
number of moles in sodium acetate = 0.5 +0.010 = 0.51
new pH
pH = pKa + log ![\frac{[base]}{[acid]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D)
pH= 4.74 + log[0.51] - log[0.49]
pH= 4.75
PH of NaOH of 0.01 M (BASE)
pOH = -Log[0.01]
pOH = 2
pH can be calculated as
14= pH +pOH
pH= 14-2
pH = 12
Answer:
<h2>The answer is 28.2 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of table = 12 cm³
density = 2.35 g/cm³
The mass of the table is
mass = 2.35 × 12
We have the final answer as
<h3>28.2 g</h3>
Hope this helps you
(a) at the bottom - high density organic compound dissolved in methylene chloride
(b) at the bottom - saturated aqueous sodium chloride
Explanation:
Sodium chloride is dissolved in water while the organic compounds are dissolved in methylene chloride. After mixing the two solutions two layers will form because water (polar molecule) will not mix with the methylene chloride (nonpolar molecule).
The layer with higher density will be at the bottom.
(a) saturated aqueous sodium chloride (d = 1.2 g/mL) - upper layer
high density organic compound dissolved in methylene chloride (d = 1.4 g/mL) - bottom layer
(b) saturated aqueous sodium chloride (d = 1.2 g/mL) - bottom layer
low density organic compound dissolved in methylene chloride (d = 1.1 g/mL) - upper layer
Learn more about:
liquids with different densities
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