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Fittoniya [83]
3 years ago
5

Is 70 thousand written in standard form or word for? Explain

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

- Question -

Is 70 thousand written in standard form or word form? Explain.

- Answer-

Neither

- Explanation -

If it were written in standard form, it would have been written like this: 70,000

If it were written in word for it would have been written like this: Seventy-Thousand

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A zoo randomly sampled three groups of 100 people on what their favorite type of bear is. The data shows the results of the thre
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Answer:

1555 people

Step-by-step explanation:

First, average the votes for polar bears.

(46 + 43 + 49)/3 = 46

Next, make the variable x equal to the estimate of the number of people who will prefer polar bear out of the 3380 people and set up your proportion equation.

x/3380 = 46/100

x = 1554.8

Round to the nearest whole number to get 1555.

3 0
3 years ago
Has a checking account used three times used another twice how much will he be charged
stira [4]
It will be charged 5 times
7 0
4 years ago
For which inequality is x=5 a solution?
chubhunter [2.5K]

Answer:

C

Step-by-step explanation:

Just replaced the x with 5 and check if it is a true statement

8 0
3 years ago
A lottery ticket which pays $1 million dollars will only cost you $1 dollar. To win a person must match 5 numbers from a total o
slavikrds [6]

The total combinations of 5 numbers that can be made from 59 numbers is:

59C5 = 5,006,386

So the probability of winning is:

P = 1 / 5,006,386

P = 1.997 x 10^-7

 

So the expected payoff is:

P = $1,000,000 (1.997 x 10^-7) - $1 (1 - 1.997 x 10^-7)

<span>P = - $0.80           (loss)</span>

<span>
</span>

<span>D</span>

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2
saul85 [17]

\large\underline{\sf{Solution-}}

<u>Let us assume that:</u>

\sf \longmapsto x =  \sqrt{6 +  \sqrt{6 +  \sqrt{6 + ... \infty } } }

We can also write it as:

\sf \longmapsto x =  \sqrt{6 +  x }

Squaring both sides, we get:

\sf \longmapsto  {x}^{2}  =6 +  x

\sf \longmapsto  {x}^{2} - x - 6  =0

By splitting the middle term:

\sf \longmapsto  {x}^{2} - 3x + 2x - 6  =0

\sf \longmapsto x(x - 3) + 2(x - 3 ) =0

\sf \longmapsto (x+ 2)(x - 3 ) =0

<u>Therefore:</u>

\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}

\sf \longmapsto x =  - 2,3

<u>But x cannot be negative. </u>

\sf \longmapsto x = 3

Therefore, the value of the expression is 3.

\large\underline{\sf{Verification-}}

Given:

\sf\longmapsto x=3

We can also write it as:

\sf\longmapsto x = \sqrt{9}

\sf\longmapsto x = \sqrt{6+3}

\sf\longmapsto x = \sqrt{6 + \sqrt{9}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}

This pattern will continue.

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}

7 0
3 years ago
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