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aivan3 [116]
3 years ago
12

If 0.25 liters of solution contains 0.030 moles of KOH what is the molarity of the solution?

Chemistry
1 answer:
sdas [7]3 years ago
7 0

Answer:

The molarity of the solution is 0,12 M.

Explanation:

We calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case KOH) in 1000ml of solution (1 liter):

0,25 L solution----- 0,030 moles of KOH

1 L solution----x= (1 L solution x 0,030 moles of KOH)/0,25 L solution

x= 0,12 moles of KOH ---> <em>The solution is 0,12 M</em>

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Answer:

Concentration of original solution = 1.66

Explanation:

We know that

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We have given concentration of NaOH = 0.1678

Volume of NaOH = 19.88 mL = 0.01988 L

So moles of NaOH = volume x concentration of NaOH

= 0.01988\times 0.1678=0.00333mole

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3 years ago
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Answer:

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3 years ago
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For the reaction NH4NO3 (s) → N2O (g) + 2H2O (l), you decompose 1 mole NH4NO3 and only get 0.75 moles of N2O. The percent yield
attashe74 [19]

Answer:

The answer to your question is False.

Explanation:

Data

1 mole of NH₄NO₃

0.75 moles of N₂O

Percent yield = 25%

Chemical reaction

               NH₄NO₃   ⇒   N₂O  +  2H₂O

Process

1.- Determine the theoretical yield

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2.- Calculate the percent yield

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-Simplification

              Percent yield = 0.75 x 100

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Conclusion

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