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3 years ago

What is the electron configuration of a chlorine ion in a compound of BeCl2?

2 answers:

8 0

The electronic configuration of a chlorine ion in BeCl2 compound is

[2.8.8]^- (answer B)

chlorine atom gain on electron form Be to form chloride ions
chlorine atom has a electronic configuration of 2.8.7 and it gains one electron to form chloride ion with 2.8.8 electronic configuration

Brrunno [24]3 years ago

5 0

Chlorine has 7 valence electrons in the outermost shell. when it forms an ionic bond with Be, it takes in 1 electron and achieves the noble gas configuration
since it has one more electron it gains a negative charge of -1.
anion is then - Cl⁻
electronic configuration of Cl atom is - [2,8,7]
after taking in the electron Cl⁻ - [2,8.8]⁻
answer is
<span>B. [2.8.8]</span>⁻

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A photon with 2.3 eV of energy can eject an electron from potassium. What is the corresponding wavelength of this type of light?

Ira Lisetskai [31]

Answer:

$\lambda=540.16\ nm$

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy = $2.3\times 1.60\times 10^{-19}\ J=3.68\times 10^{-19}\ J$

Considering

$Energy=\frac {h\times c}{\lambda}$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light being bombarded

Thus,

$3.68\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$\frac{3.68}{10^{19}}=\frac{19.878}{10^{26}\lambda}$

$3.68\times \:10^{26}\lambda=1.9878\times 10^{20}$

$\lambda=5.40163\times 10^{-7}\ m=540.16\times 10^{-9}\ m$

Also,

1 m = 10⁻⁹ nm

So,

$\lambda=540.16\ nm$

3 0

4 years ago

Consider the following reaction:

Anni [7]

<span>Consider the following reaction:
2CH3OH(g)→2CH4(g)+O2(g)ΔH=+252.8kJ
Calculate the amount of heat transferred when 27.0g of CH3OH(g) is decomposed by this reaction at constant pressure.

27.0 g </span>CH3OH(g) (1 mol/ 32.05g) = 0.84 mol CH3OH(g)
ΔH =+252.8kJ = Q = 0.84 mol (252.8kJ) = 213 kJ

6 0

4 years ago

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What is the proper name for Zn(CIO)2?

Sergio [31]

Answer:

ZINC CHLORATE

Explanation:

Zinc chloride is the name of chemical compounds with the formula ZnCl2 and its hydrates.

3 0

3 years ago

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