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blsea [12.9K]
3 years ago
14

What is the electron configuration of a chlorine ion in a compound of BeCl2?

Chemistry
2 answers:
mestny [16]3 years ago
8 0
The  electronic  configuration  of  a   chlorine ion  in BeCl2  compound is

[2.8.8]^-  (answer  B)

chlorine  atom  gain  on electron form Be to  form  chloride ions
chlorine  atom  has  a  electronic   configuration of  2.8.7   and  it  gains one  electron  to  form  chloride ion  with  2.8.8  electronic  configuration
Brrunno [24]3 years ago
5 0
Chlorine has 7 valence electrons in the outermost shell. when it forms an ionic bond with Be, it takes in 1 electron and achieves the noble gas configuration
since it has one more electron it gains a negative charge of -1.
anion is then - Cl⁻
electronic configuration of Cl atom is - [2,8,7]
after taking in the electron Cl⁻ - [2,8.8]⁻
answer is 
<span>B. [2.8.8]</span>⁻
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Cacl2+na3po4 ca3po42 + nacl
Alex787 [66]
<h3>Answer:</h3>

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

<h3>Explanation:</h3>

We are given the Equation;

CaCl₂ + Na₃PO₄→ Ca₃(PO₄)₂ + NaCl

Assuming the question requires us to balance the equation;

  • A balanced chemical equation is one that has equal number of atoms of each element on both sides of the equation.
  • Balancing chemical equations ensures that they obey the law of conservation of mass in chemical equations.
  • According to the law of conservation of mass in chemical equation, the mass of the reactants should always be equal to the mass of the products.
  • Balancing chemical equations involves putting appropriate coefficients on the reactants and products.

In this case;

  • To balance the equation we are going to put the coefficients 3, 2, 1, and 6.
  • Therefore; the balanced equation will be;

3CaCl₂ + 2Na₃PO₄→ Ca₃(PO₄)₂ + 6NaCl

5 0
3 years ago
22.5 g of silver nitrate reacts with excess magnesium bromide, determine the mass
Setler [38]

Answer:

9.82 g of Mg(NO₃)₂

Explanation:

Let's determine the reaction:

2AgNO₃  +  MgBr₂  → Mg(NO₃)₂  +  2AgBr

2 moles of nitrate silver reacts with MgBr₂ in order to produce 1 mol of magnesium nitrate and silver bromide.

We determine the moles of AgNO₃

22.5 g . 1mol / 169.87g = 0.132 moles

Ratio is 2:1.

2 moles of silver nitrate can produce 1 mol of magnesium nitrate

Then, our 0.132 moles may produce (0.132 . 1)/ 2 = 0.0662 moles

We convert moles to mass:

0.0662 mol . 148.3 g/ mol = 9.82 g

6 0
2 years ago
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC
diamong [38]

Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = 25^oC=273+25=298K

V = volume = 4.0 L

n_1 = moles of SO_2 = 0.20 mol

n_2 = moles of O_2 = 0.20 mol

Now put all the given values in the above expression, we get:

P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}

P=2.4atm

Thus, the pressure in the flask after reaction complete is, 2.4 atm

5 0
3 years ago
The difference in elevation between the highest and lowest contour lines on a topographical map is called:
Elena L [17]
I think the answer is D
7 0
3 years ago
(03.03 LC)
scoundrel [369]
I believe the answer is option B. The bonded pair of valence electrons are shown using circles
8 0
3 years ago
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