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3 years ago

9

The sum of four consecutive odd integerd is -72.

1 answer:

Solnce55 [7]3 years ago

8 0

n, n + 2, n + 4, n + 6 - four consecutive odd integers

-72 - the sum

The equation:

n + (n + 2) + (n + 4) + (n + 6) = -72

n + n + 2 + n + 4 + n + 6 = -72

4n + 12 = -72 |subtract 12 from both sides

4n = -84 |divide both sides by 4

n = -21

n + 2 = -21 + 2 = -19

n + 4 = -21 + 4 = -17

n + 6 = -21 + 6 = -15

Answer: -21, -19, -17, -15.

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Answer:

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$\left \{ {{2(0.4x + 0.3y) = 2 * 1.7} \atop {3(0.7x - 0.2y) = 3 * 0.8}} \right.$

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2 years ago

What is the solution to this system of equations?

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3 years ago

What is the slope intercept form of the equation 12x-4y=-20 y=3x+5 y=-3x-5 y=12x-20 y=20y-12x

lyudmila [28]

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Step-by-step explanation:

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3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

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see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

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in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

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Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

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Step $3$

<u>Find the distance AC</u>

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Substitute the values in the formula

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Step $4$

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Substitute the values in the formula

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<u>Find the area of the triangle</u>

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substitute the values

$A=\frac{1}{2}*8*6$

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