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Darya [45]
3 years ago
12

A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil

l be the volume of the balloon if 0.20 moles of gas are added?
Chemistry
2 answers:
Vaselesa [24]3 years ago
5 0

Answer: 1.6L

Explanation:

V1 = 1.50 L,

V2 =?

n1 = 3mol

n2 = 3 + 0.2 = 3.2mol

From PV = nRT

V1 /n1 = V2/n2

1.5/3 = V2 /3.2

V2 = (1.5/3/) x 3.2 = 1.6L

n200080 [17]3 years ago
3 0

Answer:

V = 1.6 L

Explanation:

assuming ideal gas:

  • PV = RTn

∴ R = 0.082 atm.L/K.mol

∴ V1 = 1.50 L

∴ n1 = 3.00 mol

∴ T1 = 25°C ≅ 298 K

⇒ P1 = (RT1n1)/(V1) = ((0.082 atm.L/K.mol)(298 K)(3.00 mol))/(1.50 L)

⇒ P1 = 48.872 atm

with pressure and temperature held constant:

∴ T2 = T1 = 298 K

∴ P2 = P1 = 48.872 atm

∴ n2 = 0.20 mol + 3.00 mol = 3.20 mol

⇒ V2 = (RT2n2)/P2

⇒ V2 = ((0.082 atm.L/K.mol)(298 K)(3.20 mol))/(48.872 atm)

⇒ V2 = 1.6 L

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Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.6 L  

V₂ = ?

P₁ = 1.0 atm

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Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}

{V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L

{V_2}=0.27\ L

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

7 0
3 years ago
How many grams of dry nh4cl need to be added to 2.00 l of a 0.600 m solution of ammonia, nh3, to prepare a buffer solution that
Brrunno [24]
Nh4cl = 117.165 gram ( solution is attached )

8 0
3 years ago
When you rub an inflated balloonon your head on a dry day,it can make your hair stand up! what force is that?
Ket [755]

When you rub an inflated balloon on your head and it makes your hair stand up, the force that makes the hair stand up is known as static electricity.

When the balloon is rubbed on the head, electrons from the hair atoms move into the balloon, thus making the balloon to be negatively charged and the hair positively charged due to loss of electrons.

Unlike charges attracts. Thus, when you try to pull the balloon away slowly, the positively charged hair and the negatively charged balloon will attract each other and this is usually what makes the hair stand up.

More on static electricity can be found here: brainly.com/question/24160155

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Number of moles in 31.99g O2 <br> And 176.8g NaCl
sergey [27]

#O_2

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}

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2 years ago
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