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SVEN [57.7K]
3 years ago
6

A student noticed while doing the neutralization experiment that the calorimeter kept getting warmer. how would this error affec

t the final calculation for the δhneut of each reaction? would it be overestimated, underestimated or remain unaffected? explain your reasoning.
Chemistry
1 answer:
fiasKO [112]3 years ago
8 0
The result will be underestimated since heat is lost to surrounding air. Enthalpy change of neutralisation will thus be lower than actual
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Answer:

The correct answer is option C. The unknown solution definitely has Hg22+ present.

Explanation:

In the analysis of group 1 metal cation, the unknown solution is treated with sufficient quantity of 6 M HCl solution and if group 1 metal cations are present then white precipitate of Agcl, PbCl2 or Hg2Cl2 is formed. The precipitate of PbCl2 is soluble in hot water but the other two remains insoluble after treating with hot water. Precipitate of AgCl disappears upon treatment of NH3 solution but Hg2Cl2 becomes black in the reaction with NH3. The black Colour appears due to the formation of metallic Hg.

Balanced chemical equation of the reation is -

Hg2Cl2 + 2NH3  ---------> HgNH2Cl (white ppt.) + Hg (black ppt.) + NH4Cl

Therefore, from the given information the conclusion which can be drawn is that the unknown solution definitely has Hg22+ present.

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Answer:

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Elena L [17]

<u>Answer:</u>

For 1: The correct answer is Option D.

For 2: The correct answer is Option A.

<u>Explanation:</u>

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Polar molecules are defined as the of molecules, in which two atoms that combine must be of different element and therefore can create a dipole. For a dipole, there must be a difference in electronegativity and that is achieved when two atoms of different electronegativity combine. The negative dipole or charge is created on the electronegative atom and positive dipole or charge is created on the electropositive atom.

Thus, the correct answer is option D.

  • <u>For 2:</u>

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Thus, the correct answer is A.

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