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Crazy boy [7]
3 years ago
12

What is true of a covalent bond? (03.03)

Chemistry
2 answers:
garri49 [273]3 years ago
6 0

Answer:

I think B..

Explanation:

It is the sharing of electrons from one atom to another .

Brrunno [24]3 years ago
5 0

Answer:

The answer is b: It is the sharing of electrons by overlapping orbitals

Explanation:

The ionic bong involves the exchange of electrons from one atom to another to keep eight particles in their outermost orbit. In this way the atoms become stable.  This happens between a metal, which losing electrons becomes a cation that now has a positive charge, and a non-metal, which accepting electrons becomes an anion that now has a negative charge. So the ionic bond is the electrostatic attraction between oppositely charged particle (cation and anion).

No chemical bond involves sharing neutrons between two nuclei. Chemical bonds occur between the electrons of atoms, which are found in the outer layer around the nuclei.

So, the correct answer is b: It is the sharing of electrons by overlapping orbitals.  This happens between two non-metallic elements.

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Avoid of diseases in monsoon season-
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Monsoon seasonal diseases can be avoided by keeping surroundings clean, removing stagnant water, eating homemade food, washing hands properly, eating clean and drinking boiled water.

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4 0
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1. Methane (CH4) combusts as shown in the equation below. If 3 moles of methane were used in the combustion, what would be the c
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Answer:

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

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<u>Step 1: </u>The balanced equation

CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g)   ΔH = -802 kJ

<u>Step 2:</u> Given data

We notice that for 1 mole of methane (CH4), we need 2 moles of O2 to produce : 1 mole of CO2 and 2 moles of H20.

The enthalpy change of combustion, given here as  Δ H , tells us how much heat is either absorbed or released by the combustion of <u>one mole</u> of a substance.

In this case: we notice that the combustion of 1 mole of methane gives off (because of the negative number),  802.3 kJ  of heat.

<u>Step 3: </u>calculate the enthalpy change  for 3 moles

The -802 kj is the enthalpy change for 1 mole

The change in enthalpy for 3 moles = 3* -802 kJ = -2406 kJ

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

5 0
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