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ozzi
3 years ago
11

What is the graph of the function f(x)=x2-9x+20/x-4

Mathematics
1 answer:
Kipish [7]3 years ago
4 0
Y=((x-5)(x-4))/(x-4)

y=x-5  
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I was able to get the first two parts and now I am stumped.
Aleksandr [31]

The correct response that would be expected based on the probability information is 164

<h3>How to depict the values?</h3>

From the information, there were 352 trials that were made and we're correct 164 times.

Therefore, the correct response that would be expected is 164.

The success rate will be:

= 164/352

= 0.466

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

4 0
2 years ago
Please help for brainliest
finlep [7]

Answer:

8a : No because only the boys have a say and girls are part of the school to

8b: The question is random because it just asks it would be biased if it said what is your favorite sport fun basketball of boring soccer because it uses adjectives.

Hope this helps I just learned about it last year

Step-by-step explanation:

4 0
3 years ago
The answer ASAP plz I need help
Alex Ar [27]

Answer:

C

Step-by-step explanation:

i might be wrong -

7 0
3 years ago
Read 2 more answers
Michelle is building a rectangular landing strip for airplanes .She has material to cover 1/1,500 of a square mile. The landing
ANEK [815]
I think that the missing word here is:
"with the amount of the material that Michelle has"

Let's say that her landing strip is x miles long, then its area would be:


\frac{1}{6} *x

We also know how big it is:

\frac{1}{6} *x= \frac{1}{1 500}

now, let's multiply both sides by 6:
\frac{6}{6} *x= \frac{6}{1 500}
1 *x= \frac{3}{750}
x= \frac{1}{250}


So the answer is that it would be x= \frac{1}{250} miles wide






3 0
4 years ago
Find the area of the figure.<br> A-56cm^2<br> B-88cm^2<br> C-112cm^2<br> D-384cm^2
julia-pushkina [17]
  • firstly find the area of the square which is sidexside=8x8=64cm^2
  • then find the area of the triangle which is 1/2xbasexhight=1/2x8x6=24cm^2
  • THEN add both areas (64+24)=88cm^2

4 0
3 years ago
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