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dangina [55]
3 years ago
14

Given Bold u equals negative Bold i plus Bold j​, Bold v equals 10 Bold i minus 2 Bold j​, and Bold w equals negative 8 Bold j​,

find proj Bold Subscript u left parenthesis Bold v plus Bold w right parenthesis.
Given u=-i+j, v=10i-2j, and w =-8j

find proj Subscript u (v+w)
Mathematics
2 answers:
OverLord2011 [107]3 years ago
8 0

Answer: u.(v+w) = -20

Step-by-step explanation:

Given;

u = -i+j

v = 10i-2j

w = -8j

v+w = 10i-2j +(-8j)

v+w = 10i-10j

u .(v+w) = (-i+j).(10i-10j)

= -1×10 + 1 ×-10

= -10-10

u.(v+w) = -20

Travka [436]3 years ago
8 0

Answer: u(v+w) = - 20

Step-by-step explanation: u, v and w are vectors in the x-y plane, where i is related to the x-axis and j is related to the y-axis. Vectors can be added, subtracted or "perform" an operation called dot product.

In this question, we have: u.(v + w)

To resolve it, first add the vectors:

(v + w) = (10i - 2j) + (-8j)

(v + w) = (10i - 10j)

Now, the dot product:

u . (v + w) = (-i + j) . (10i - 10j)

u . (v + w) = (-1)(10) + (1).(-10)

u . (v + w) = - 10 - 10

u . (v + w) = - 20

Note that the sum of vector gave another vector. However, the dot product of vectors produce a scalar because it's the sum of the product of the horizontal elements with the sum of the product of the vertical elements.

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Which functions have a vertex with a x-value of 0? select three options. f(x) = |x| f(x) = |x| 3 f(x) = |x 3| f(x) = |x| − 6 f(x
Doss [256]

The functions have a vertex with a x-value of 0 will be f(x) = |x|,f(x) = |x|+ 3 and f(x) = |xl - 6.Option 1,2 and 4 are  functions have a vertex with a x-value of 0.

<h3>What is a function?</h3>

A connection between independent variables and the dependent variable.is defined by the function. Functions help to represent graphs and equations.

The standard absolute value function is found as;

\rm f(x) = a|x - h| + k

Where,

(h, k) denotes to the vertex

h is the vertex of the x-coordinate

k is the y-coordinate of the vertex

By comparing the standard equation with the given equation in the options we will get the functions to have a vertex with an x-value of 0;

\rm f(x)  =  |x| \\\\ \rm f(x) = |x|  +  3 \\\\ f(x) = |x|  -  6

The functions have a vertex with a x-value of 0 will be f(x) = |x|,f(x) = |x|+ 3 and f(x) = |xl - 6.Option 1,2 and 4 are  functions have a vertex with a x-value of 0.

Hence options 1,2 and 4 are functions that have a vertex with an x-value of 0.

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brainly.com/question/12431044

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weqwewe [10]

Given that Martin throws a ball straight up in the air.

The equation h(t)=-16t^2+40t+5 gives the height of the ball, in feet, t seconds after martin releases it.

We need to determine the time that it takes the ball to hit the ground.

<u>Time taken:</u>

To determine the time 't', let us equate h(t) = 0 in the equation h(t)=-16t^2+40t+5

Thus, we have;

0=-16t^2+40t+5

Switch sides, we get;

-16 t^{2}+40 t+5=0

Now, we shall solve the equation using the quadratic formula.

Thus, we have;

t=\frac{-40 \pm \sqrt{40^{2}-4(-16) 5}}{2(-16)}

Solving, we get,

t=\frac{-40 \pm \sqrt{1600+320}}{-32}

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Cancelling the common terms, we get,

t=\frac{-5 \pm \sqrt{30}}{-4}

Thus, the roots of the equation t=\frac{-5 + \sqrt{30}}{-4} and t=\frac{-5 - \sqrt{30}}{-4}

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Hence, It takes 2.6 seconds for the ball to hit the ground.

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Answer:

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