1 molecule of NO2 included N atom and 2 oxygen atoms, so a total of 3 atoms per molecule.
1.3 x 10^22 times 3 = 3.9 x 10^22 atoms
Answer:
Zero to the power of zero, denoted by 00, is a mathematical expression with no agreed-upon value. The most common possibilities are 1 or leaving the expression undefined, with justifications existing for each, depending on context
Explanation:
Answer:
Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)
Explanation:
Given:
Mass M1 = 26 kg
Mass M2 = 5.1 kg
Distance r = 0.19 m
Find:
Gravitational force of attraction G(f)
Computation:
Gravitational force of attraction G(f) = G(m1)(m2)/r²
Gravitational force of attraction G(f) = [6.67 x 10⁻¹¹](26)(5.1)/(0.19)²
Gravitational force of attraction G(f) = 8.84 x 10⁻⁹ / 0.0361
Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)
Answer:
The
of a substrate will be "10 μM".
Explanation:
The given values are:

![[Substract] = 40 \ \mu M](https://tex.z-dn.net/?f=%5BSubstract%5D%20%3D%2040%20%5C%20%5Cmu%20M)

Reaction velocity, 
As we know,
⇒ ![Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}](https://tex.z-dn.net/?f=Vo%3D%5Cfrac%7BK_%7Bcat%7D%5BE_%7Bt%7D%5D%5BS%5D%7D%7BK_%7Bm%7D%2B%5BS%5D%7D)
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
On subtracting "40" from both sides, we get
⇒ 
⇒ 
Properties of a solution that depend only on the ratio of the number of particles of solute and solvent in the solution are known as colligative properties. For this problem, we use boiling point elevation concept.
ΔT(boiling point) = (Kb)mi
ΔT(boiling point) = (0.51 C-kg / mol )(4.0 mol / 2.05 kg ) (2)
ΔT(boiling point) = 1.99 C
T(boiling point) = 101.99 C